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Tema [17]
3 years ago
6

Imagine a solution of two liquids that are so similar that their interactions together are the same as in the individual liquids

. will this solution deviate positively from, deviate negatively from, or ideally follow raoult's law?
Chemistry
1 answer:
Lisa [10]3 years ago
3 0
Answer:
<span>ideally follow Raoult's law</span>

Explanation:
Raoult's law states that: "<span>the partial </span>vapor pressure<span> of each component of an </span>ideal mixture<span> of liquids is equal to the vapor pressure of the pure component multiplied by its </span>mole fraction<span> in the mixture"
</span>
It is given that:
1- the two solutions are similar
2- <span>their interactions together are the same as in the individual liquids

This means that the solution formed will be an ideal solution. This means that the vapor pressure formed will be exactly equal to that predicted by Raoult's law.

Hope this helps :)</span>
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A solution contains 0.60 mg/ml mn2+. what minimum mass of kio4 must me added to 5.00 ml of the solution in order to completely o
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The given solution of Mn²⁺ is 0.60 mg/mL.
Hence mass of Mn²⁺ in 5 mL of solution = 0.60 mg/mL x 5 mL = 3 mg

Molar mass of Mn = 54.9 g/mol
Hence, moles of Mn²⁺ = 3 x 10⁻³ g / 54.9 g/mol = 5.46 x 10⁻⁵ mol

The balanced equation for the reaction is,
2Mn²⁺ + 5KIO₄ + 3H₂O → 2MnO₄⁻ + 5KIO₃ + 6H⁺

The stoichiometric ratio between Mn²⁺ and KIO₄ is 2 : 5

Hence, moles of KIO₄ reacted = 5.46 x 10⁻⁵ mol x (5 / 2)
                                                 = 13.65 x 10⁻⁵ mol
Molar mass of KIO₄ = 230 g/mol

Hence needed mass of KIO₄ = 13.65 x 10⁻⁵ mol x 230 g/mol
                                               = 0.031395 g
                                               = 31.395 mg
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3 years ago
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