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3 years ago

To determine the mass of CO2 that forms from a given mass of CaCO3, which of the following must be known? Check all that apply.

Chemistry

2 answers:

Pavlova-9 [17]3 years ago

7 0

Answer:

1 3 and 5

Explanation:

ZanzabumX [31]3 years ago

3 0

To determine the mass of CO₂, the following must be known :

the molar mass of CaCO₃
the mole ratio of CaCO₃ to CO₂
the molar mass of CO₂

<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

Given the mass of CaCO₃, so to determine the mass of CO₂ :

1. Find the mol of CaCO₃ from the molar mass of CaCO₃

$\tt n_{CaCO_3}=\dfrac{mass~CaCO_3}{MW~CaCO_3}$

2. Find the mole ratio of CaCO₃ : CO₂(from equation = 1 : 1)

$\tt n_{CaCO_3}\div n_{CO_2}=1\div 1$

3. Find the mass of CO₂ from the molar mass of CO₂

$\tt mass_{CO_2}=n_{CO_2}\times MW_{CO_2}$

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which of these is an example of a chemical change A breaking glass B mealting ice on a windshield C burning gasoline D denting a

Nonamiya [84]

Lets do process of elimination!

A. Breaking glass - That is a psychical change because if you break it, it is still glass. It didn't change to another substance.

B. Melting ice on a windshield - During the melting process, there is no chemical change, and therefore, no new substance is created.

C. Burning gasoline - When gas burns it usually combines with oxygen to give carbon dioxide, water etc. It is a chemical change.

D. Denting a bumper - The bumper is still a bumper, only thing is it has a dent in it. The properties did not change, meaning no chemical change.

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3 years ago

Read 2 more answers

Classify each of the following compounds as a strong acid, weak acid, strong base, or weak base, and write the Ka expression for

Katyanochek1 [597]

Answer:

See explanation below

Explanation:

There are several ways to know if an acid or base is strong. One method is calculating the pH. If the pH is really low, is a strong acid, and if it's really high is a strong base.

However we do not have a pH value here.

The other method is using bronsted - lowry theory. If an acid is strong, then his conjugate base is weak. Same thing with the bases.

Now, Looking at the 4 compounds, we can say that only two of them is weak and the other two are strong compounds. Let's see:

LiOH ---> Strong. If you try to dissociate :

LiOH ------> Li⁺ + OH⁻ The Li⁺ is a weak conjugate acid.

HF -----> Weak

HF --------> H⁺ + F⁻ The Fluorine is a relatively strong conjugate base.

HCl -----> Strong

This is actually one of the strongest acid.

NH₃ ------> Weak

Now writting the Ka and Kb expressions:

Ka = [H⁺] [F⁻] / [HF]

Kb = [NH₄⁺] [OH⁻] / [NH₃]

Finally, to calculate the [OH⁻] we need to use the following expression:

Kw = [H⁻] [OH⁻]

Solving for [OH⁻] we have:

[OH⁻] = Kw / [H⁺]

Remember that the value of Kw is 1x10⁻¹⁴. So replacing:

[OH⁻] = 1x10⁻¹⁴ / 7x10⁻⁶

[OH⁻] = 1.43x10⁻⁹ M

And now, multiplying by 10¹⁰ we have:

[OH⁻] = 1.429x10⁻⁹ * 1x10¹⁰

Hope this helps

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3 years ago

Which type of molecule is shown below?

zubka84 [21]

Answer:

$\boxed{\mathrm{Alkene}}$

Explanation:

The hydrocarbon shown has a double bond. Hydrocarbons with double bonds are known as alkenes.

Cyclic alkanes have cyclic structure.

Alkanes only have single bonds.

Alkynes have triple bonds.

8 0

3 years ago

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How many moles of oxygen are required to produce 37.15 g CO2? 37.15 g CO2 = mol O2

NNADVOKAT [17]

Answer:

0.84 moles of oxygen are required.

Explanation:

Given data:

Mass of CO₂ produced = 37.15 g

Number of moles of oxygen = ?

Solution:

Chemical equation:

C + O₂ → CO₂

Number of moles of CO₂:

Number of moles = mass/molar mass

Number of moles = 37.15 g/ 44 g/mol

Number of moles = 0.84 mol

Now we will compare the moles of oxygen and carbon dioxide.

CO₂ : O₂

1 : 1

0.84 : 0.84

0.84 moles of oxygen are required.

6 0

3 years ago

Read 2 more answers

The ΔHcomb value for anethole is -5539 kJ/mol. Assume 0.840 g of anethole is combusted in a calorimeter whose heat capacity (Cal

bonufazy [111]

Answer:

Final temperature of calorimeter is 25.36^{0}\textrm{C}

Explanation:

Molar mass of anethole = 148.2 g/mol

So, 0.840 g of anethole = $\frac{0.840}{148.2}moles$ of anethole = 0.00567 moles of anethole

1 mol of anethole releases 5539 kJ of heat upon combustion

So, 0.00567 moles of anethole release $(5539\times 0.00567)kJ$ of heat or 31.41 kJ of heat

6.60 kJ of heat increases $1^{0}\textrm{C}$ temperature of calorimeter.

So, 31.41 kJ of heat increases $(\frac{1}{6.60}\times 31.41)^{0}\textrm{C}$ or $4.76^{0}\textrm{C}$ temperature of calorimeter

So, the final temperature of calorimeter = $(20.6+4.76)^{0}\textrm{C}=25.36^{0}\textrm{C}$

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4 years ago