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Bond [772]
3 years ago
7

To determine the mass of CO2 that forms from a given mass of CaCO3, which of the following must be known? Check all that apply.

Chemistry
2 answers:
Pavlova-9 [17]3 years ago
7 0

Answer:

1 3 and 5

Explanation:

ZanzabumX [31]3 years ago
3 0

To determine the mass of CO₂, the following must be known :

  • the molar mass of CaCO₃
  • the mole ratio of CaCO₃ to CO₂
  • the molar mass of CO₂
<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

Given the mass of  CaCO₃, so to determine the mass of CO₂ :

1. Find the mol of  CaCO₃ from the molar mass of  CaCO₃

\tt n_{CaCO_3}=\dfrac{mass~CaCO_3}{MW~CaCO_3}

2. Find the mole ratio of  CaCO₃ : CO₂(from equation = 1 : 1)

\tt n_{CaCO_3}\div n_{CO_2}=1\div 1

3. Find the mass of CO₂ from the molar mass of CO₂

\tt mass_{CO_2}=n_{CO_2}\times MW_{CO_2}

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a- If an Lithium (atomic number 3) atom has a -2 charge, how many electrons does it have? b- Why do you do it this way? c- Is th
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Answer:

5

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6 0
2 years ago
If 1.16 L of water is initially at 24.2 ∘C, what will its temperature be after absorption of 9.4×10−2 kWh of heat?
vitfil [10]

Answer:

The temperature will be 93.92 °C

Explanation:

To explain this we will use following equation: also  Q = ∆U + W known as the NON-FLOW ENERGY EQUATION (N.F.E.E.)

With Q = heat added to the system

with ∆U  = change in internal energy

⇒∆U = ( m )( Cv )( T2 - T1 )

With W = work done by the system

⇒For this situation W = 0 because there isn't work done

So we get: ∆U = ( m )( Cv )( T2 - T1 ) = Q

To find the temperature, we have to isolate T in the equation:

(T2-T1) = Q / (m)(Cv)

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mass = 1000g/L * 1.16 L = 1160g

Cv = heat capacity ⇒ water has a  heat capacity of 4.184 J/g °C

We know the absorption of heat is 9.4x 10^-2 kWh but to know how many joule this is we should convert ( 1 joule = 3.6 x 10^6 kWh)

⇒Q = ( 0.094 kWh ) ( 3.6 x 10^6 J / kWh ) = 0.3384 x 10^6 J

For the temperature we get then: T2 -T1 = Q / (m)(Cv)

T2 - T1 =  0.3384 x 10^6 J / (( 1160g)*(4.184 J/g °C)) = 69.72 ° C

T2 = ( T2 - T1 ) + T1   ⇒ 69.72 + 24.2 = 93.92 °C

6 0
3 years ago
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