Answer:
The answer of the part (a) is v2 = 7.09 m/s
and the answer of the part (b) is vA1 = 5.25 m/s
Explanation:
Explanation of the both parts of answer is in the following attachments
Answer:
Interference
Explanation:
When two waves of same frequency and constant phase difference super impose at a point on the screen then due to their superposition we will get different intensity of light at different positions of the screen
This phenomenon of redistribution of energy is known as interference of light.
So at the position of screen where the light intensity is maximum on the screen is known as constructive interference while the positions on the screen where it will get minimum intensity on the screen is known as destructive interference of the light
So correct answer would be
Interference
Answer:
1.84 m
Explanation:
For the small lead ball to be balanced at the tip of the vertical circle just before it is released, the reaction force , N equal the weight of the lead ball W + the centripetal force, F. This normal reaction ,N also equals the tension T in the string.
So, T = mg + mrω² = ma where m = mass of small lead ball, g = acceleration due to gravity = 9.8 m/s², r = length of rope = 1.10 m and ω = angular speed of lead ball = 3 rev/s = 3 × 2π rad/s = 6π rad/s = 18.85 rad/s and a = acceleration of normal force. So,
a = g + rω²
= 9.8 m/s² + 1.10 m × (18.85 rad/s)²
= 9.8 m/s² + 390.85 m/s²
= 400.65 m/s²
Now, using v² = u² + 2a(h₂ - h₁) where u = initial velocity of ball = rω = 1.10 m × 18.85 rad/s = 20.74 m/s, v = final velocity of ball at maximum height = 0 m/s (since the ball is stationary at maximum height), a = acceleration of small lead ball = -400.65 m/s² (negative since it is in the downward direction of the tension), h₁ = initial position of lead ball above the ground = 1.3 m and h₂ = final position of lead ball above the ground = unknown.
v² = u² + 2a(h₂ - h₁)
So, v² - u² = 2a(h₂ - h₁)
h₂ - h₁ = (v² - u²)/2a
h₂ = h₁ + (v² - u²)/2a
substituting the values of the variables into the equation, we have
h₂ = 1.3 m + ((0 m/s)² - (20.74 m/s)²)/2(-400.65 m/s²)
h₂ = 1.3 m + [-430.15 (m/s)²]/-801.3 m/s²
h₂ = 1.3 m + 0.54 m
h₂ = 1.84 m
The equivalent resistance of the circuit is 8.6 Ω.
<h3>What is resistance?</h3>
Resistance can be defined as the opposition to current flow in an electric circuit. The S.I unit of resistance is ohms.
To calculate the equivalent resistance, we use the formula below.
Formula:
- R' = R₁+(R₂//R₃)................ Equation 1
Where:
- R' = Equivalent resistance of the circuit.
From the diagram,
Given:
- R₁ = 5 .00 Ω
- R₂ = 9.00 Ω
- R₃ = 6.00 Ω
Substitute these values into equation 1
- R' = 5+(9//6)
- R' = 5+[(9×6)/(9+6)]
- R' = 5+[54/15]
- R' = 5+3.6
- R' = 8.6 Ω
Hence, The equivalent resistance of the circuit is 8.6 Ω
Learn more about equivalent resistance here: brainly.com/question/12856032
