Answer:
Acceleration, 
Explanation:
It is given that,
Time period of revolution of the moon, 
If the distance from the center of the moon to the surface of the planet is, 
The radius of the planet, 
Let a is the moon's radial acceleration. Mathematically, it is given by :
, R is the radius of orbit
Since, 
The radius of orbit is,
So, 
Hence, this is the required solution for the radial acceleration of the moon.
<span>Water will diffuse down gradients of water potential, just as heat will flow down gradients of temperature and rocks will roll down gradients of gravitational potential</span>
Answer:
B. 2nmv
Explanation:
Pressure is force over area.
P = F / A
Force is mass times acceleration.
F = ma
Acceleration is change in velocity over change in time.
a = Δv / Δt
Therefore:
F = m Δv / Δt
P = m Δv / (A Δt)
The total mass is nm.
The change in velocity is Δv = v − (-v) = 2v.
A = 1 and Δt = 1.
Plugging in:
P = (nm) (2v) / (1 × 1)
P = 2nmv
