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3 years ago

Speed is how fast an object moves a certain distance within a length of time. How is speed calculated?

Chemistry

2 answers:

GREYUIT [131]3 years ago

6 0

Answer s=d/t

Explanation:

That means speed equals distance divided by time. To solve for time use formula for time: t=d/s

MatroZZZ [7]3 years ago

5 0

S= d/t is the answer

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Habitat ____________ splits ecosystems into pieces and makes populations more vulnerable to disturbances or climate change.

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How many grams of sodium chloride are contained in 250.0 g of a 15% NaCl solution?

kramer

Given concentration of NaCl=15%

Means ,

In every 100g of Solution 15g of NaCl is present .

Now

Given mass=250g

So ,

$\\ \Large\sf\longmapsto 250\times 15\%$

$\\ \Large\sf\longmapsto 250\times \dfrac{15}{100}$

$\\ \Large\sf\longmapsto 37.5g$

37.5g of NaCl present in 250g of solution.

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The word root for a group of microorganisms living together is a. steriliz. b. prodrom. c. coloniza. d. nosocomi.

UkoKoshka [18]

The answer is C) Coloniza.

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3 years ago

A solution has a [OH-] of 1 × 10-9. What is the pOH of this solution?

zhannawk [14.2K]

POH = - log [ OH⁻ ]

pOH = - log [ 1 x 10⁻⁹ ]

pOH = 9

Answer C

hope this helps!

3 0

3 years ago

During a titration the following data were collected. A 50.0 mL portion of an HCl solution was titrated with 0.500 M NaOH; 200.

Travka [436]

Answer: The mass of HCl present in 500 mL of acid solution is 36.5 grams

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=50.00mL\\n_2=1\\M_2=0.500M\\V_2=200.mL$

Putting values in above equation, we get:

$1\times M_1\times 50.00=1\times 0.500\times 200\\\\M_1=\frac{1\times 0.500\times 200}{1\times 50.00}=2M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Molar mass of HCl = 36.5 g/mol

Molarity of solution = 2 M

Volume of solution = 500 mL

Putting values in above equation, we get:

$2mol/L=\frac{\text{Mass of solute}\times 1000}{36.5g/mol\times 500}\\\\\text{Mass of solute}=\frac{2\times 36.5\times 500}{1000}=36.5g$

Hence, the mass of HCl present in 500 mL of acid solution is 36.5 grams

4 0

3 years ago