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ra1l [238]
3 years ago
11

3 sin(x) + 3 = sin(x)

Mathematics
1 answer:
kumpel [21]3 years ago
8 0

Answer:

no solution

Step-by-step explanation:

3 sin x+3=sin x

3 sin x-sin x=-3

2 sin x=-3

sin x=-3/2

which is impossible as |sin x|≤ 1

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Solve the inequality<br> x/3 - 2 &lt;4
Afina-wow [57]

Answer:

brainliest please

Step-by-step explanation:

x/3-2<4

x/3<6

x<18

8 0
2 years ago
What is the area of these trapezoid
Assoli18 [71]

Answer:

1. 54ft squared  2. 48 cm squared

Step-by-step explanation:

6 0
2 years ago
SAT Scores 1510 1480 2100 1800 1300 1250 1400 1430 1390 1520 The SAT scores for a group of 10 students are shown. What is the me
Minchanka [31]

Answer:

1580.0

Step-by-step explanation:

- Add all numbers and divide them by 10 (the amount of numbers).

- Mean is when you add all the numbers and divide them by how many their are.

3 0
3 years ago
Write an equation that could be used to find the value of x using the interior angles of ∆BDC, then solve it.
Alecsey [184]

9514 1404 393

Answer:

  x = 16

Step-by-step explanation:

Either or both of the right triangles can be used to find x. Or, triangle ABC could be used. All numbers are assumed to be degrees.

<u>Using ∆ABD</u>

  55 +90 +2x+3 = 180

  2x = 32 . . . . . . subtract 148

  x = 16

<u>Using ∆BCD</u>

  50 +90 +2x+8 = 180

  2x = 32 . . . . . . subtract 148

  x = 16

<u>Using ∆ABC</u>

  55 +(2x +3) +50 +(2x +8) = 180

  4x = 64 . . . . . . . subtract 116

  x = 16

6 0
3 years ago
Can you help me with this problem please
Over [174]

Remark

I think you want us to do both 3 and 4


Three

QR is 4 points going left from the y axis + 2 points going right from the y axis.

QR = 6 units long.


RT is 4 units above the x axis and 3 units below the x axis

RT = 7 units long


TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.


Problem 4

You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.


Area = (b1 + b2)*h/2


Givens

B1 = QR = 6

B2 = UT + TS = 6 + 3 = 9

h = RT = 7


Area

Area = (6 + 9)*7/2

Area = 15 * 7 / 2

Area = 52.5


Comment

You could break this up into a rectangle + a triangle

Find the area of QRTU and add the Area of triangle RTS


<em>Area of the rectangle </em>= L * W

L = RT = 7

W = QR = 6

Area = 7 *6 = 42


<em>Area of the triangle</em> = 1/2 * B * H

B = TS = 3

H = RT =7

Area = 1/2 * 3 * 7

Area = 1/2 * 21

Area = 10.5


Total Area = 42 + 10.5 = 52.5 Both answers agree.

3 0
3 years ago
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