Answer:
Yes, since the choice of the zero o potential energy is arbitrary.
Explanation:
The kinetic energy is due to the motion of the object. The expression for the kinetic energy is as follows;
![KE=\frac{1}{2}mv^{2}](https://tex.z-dn.net/?f=KE%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E%7B2%7D)
Here, m is the mass of the object and v is the velocity of the object.
The kinetic energy can not be negative as the velocity is squared. It can be zero and positive.
Potential energy: It is the energy is due to the position of the object.
The expression for the potential energy is as follows;
PE= mgh
Here, g is the acceleration due to gravity and height.
Height can be taken from the reference point, zero which can be taken below zero and above zero. Zero is taken as origin. Below zero, the height is taken as negative and above zero, the height is taken as positive.
The potential energy can be zero, positive and negative.
The total energy is the sum of kinetic energy and potential energy.
E= KE + PE
Here, KE is the kinetic energy and PE is the potential energy.
Therefore, the option (B) is correct.
Particles in a SOLID have a small amount of energy, vibrate, and are stuck in place?
Answer:
option is option d)
Explanation:
the correct option is option d)
the characteristic of thunderstorm can be seen by the following scenario
in thunderstorm there is lot of movement of air the lighter i.e.warmer air moves up and the colder air moves down creating the condition of thunderstorm.
heavy rain , strong wind , potentially large hail stones is the situation of the thunderstorm.
during thunderstorm there is rain and snow at intermediate.
hence only option left is option d.
Answer:
option D
Explanation:
given,
A conductor is carrying current = 2.0 A is 0.5 mm thick
Hall voltage = 4.5 x 10-6 V
uniform magnetic field = 1.2 T
density of the charge = n =?
hall voltage =![V_h =\dfrac{i\ B}{n\ e\ L}](https://tex.z-dn.net/?f=V_h%20%3D%5Cdfrac%7Bi%5C%20B%7D%7Bn%5C%20e%5C%20L%7D)
![n = \dfrac{i\ B}{V\ e\ L}](https://tex.z-dn.net/?f=n%20%3D%20%5Cdfrac%7Bi%5C%20B%7D%7BV%5C%20e%5C%20L%7D)
![n = \dfrac{2 \times 1.2 }{4.5 \times 10^{-6}\times 1.6 \times 10^{-19} \times 0.5 \times 10^{-3}}](https://tex.z-dn.net/?f=n%20%3D%20%5Cdfrac%7B2%20%5Ctimes%201.2%20%7D%7B4.5%20%5Ctimes%2010%5E%7B-6%7D%5Ctimes%201.6%20%5Ctimes%2010%5E%7B-19%7D%20%5Ctimes%200.5%20%5Ctimes%2010%5E%7B-3%7D%7D)
n = 6.67 × 10²⁷ charges/m
hence the correct answer is option D