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3 years ago

How far will a football travel if it is booted at a speed of 15 m/s and travels for 3 seconds?

Physics

1 answer:

stealth61 [152]3 years ago

8 0

Answer:

d= 45 m

Explanation:

speed = distance / time

15= d/ 3

d= 45 m

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If a 1.3 kg mass stretches a spring 4 cm, how much will a 5.8 kg mass stretch the

Likurg_2 [28]

Answer:

17.8cm

Explanation:

1.3kg --> 4cm

1kg --> 3, 1/13cm

5.8kg --> 18.8cm

6 0

3 years ago

If a person walks 3 m north and 5 meters east, how would you find the displacement for that person? what would the displacement

UkoKoshka [18]

Answer:

AC)=(AB)2+(BC)2−−−−−−−−−−−−√=42+32−−−−−−√

⇒displacement=16+9−−−−−√=25−−√=5m

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3 years ago

Select the correct answer.

Dahasolnce [82]

Answer:

a is the correct choice

Explanation:

5 0

3 years ago

Read 2 more answers

Because of the curvature of the earth, the maximum distance D that you can see from the top of a tall building of height h is es

mojhsa [17]

Answer:

D = 9.9 10⁶ mi

Explanation:

In the exercise they give the expression for maximum viewing distance

D = 2 r h + h²

Ask for this distance for a height of 1100 feet

Let's calculate

D = 2 3960 1100 + 1100²

D = 8.712 10⁶ + 1.21 10⁶

D = 9.92 10⁶ mi

D = 9.9 10⁶ mi

8 0

3 years ago

The height of a projectile t seconds after it is launched straight up in the air is given by f (t )equals negative 16 t squared

velikii [3]

Answer:

$\displaystyle a(5)=-32$

Explanation:

<u>Instant Acceleration</u>

The kinetic magnitudes are usually related as scalar or vector equations. By doing so, we are assuming the acceleration is constant over time. But when the acceleration is variable, the relations are in the form of calculus equations, specifically using derivatives and/or integrals.

Let f(t) be the distance traveled by an object as a function of the time t. The instant speed v(t) is defined as:

$\displaystyle v(t)=\frac{df}{dt}$