Answer:
final volume the balloon occupy in instant before it burst is 4.634 L
Explanation:
given data
helium filled V1 = 2 L
initially pressure P1 = 1.25 atm
finally pressure P2 = 410 mmHg
1 atm = 760 mmHg
to find out
at what volume the balloon occupy in instant before it burst
solution
we have given
760 mmHg = 1atm
and 1 mmHg = 1/760
so 410mmHg = 410/760 atm
so that final pressure is = 410/760 atm
we use here Boyle's Law that is
Boyle's law states that "the volume of an ideal gas is inversely proportional to the pressure of the gas at constant temperatures"
so P ∝ 1/V
P1V1 = P2V2
V2 = P1V1 / P2
put all value
V2 = 1.25 (2) / (410/760)
V2 = 2.5 / 0.53947 = 4.634
so final volume the balloon occupy in instant before it burst is 4.634 L
Answer:
they carry a heavier load
Explanation:
Friction = 0.25 * m * g = 10.8
Push = m * a + Friction = 4.4 * 1.5 + 10.8
Yes it may or may not be depending on the angle of the ramp. But if nothing is specified then it must be related to acceleration as friction is neglected.
