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IgorC [24]
2 years ago
11

Please help, I'm really struggling here, I can't do science :(

Physics
1 answer:
mestny [16]2 years ago
3 0

Answer:no sure sorry

Explanation:

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Two identical light springs with spring constant k3 are now individually hung vertically from the ceiling and attached at each e
anyanavicka [17]

Answer:

 Keq = 2k₃

Explanation:

We can solve this exercise using Newton's second one

                F = m a

Where F is the eleatic force of the spring F = - k x

Since we have two springs, they are parallel or they are stretched the same distance by the object and the response force Fe is the same for the spring age due to having the same displacement

          F + F = m a

         k₃ x + k₃ x = m a

         a = 2k₃  x / m

To find the effective force constant, suppose we change this spring to what creates the cuddly displacement

       Keq = 2k₃

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3 years ago
There are both enviromental and food stimuli that can disrupt sleep true or false
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The answer is true. I hope that this helps you out!!
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The sun's core _____. A) is made of solid helium B) makes up most of the sun's size C) creates energy by fusing hydrogen into he
VashaNatasha [74]
I think the correct answer is C
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3 years ago
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Which example provides a complete scientific description of an object in motion? the vibration of the jackhammer broke through t
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The hiker followed the north trail a distance of two kilometers in thirty minutes is an example that provides a complete scientific description of an object in motion.

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A lead nucleus is spherical with a radius of about 7 ✕ 10⁻¹⁵ m. The nucleus contains 82 protons (and typically 126 neutrons). Be
Komok [63]

Answer:

∈=3.1584x10^{26} \frac{V}{m}

Explanation:

Using the Gauss Law to determine the electric field of the net flux at the surface of the nucleus

∈=\frac{P}{E_{o}}

The P is the charge density and 'Eo' is the constant of permittivity in free space

to find P

P=\frac{q}{V}

V=\frac{4}{3}*\pi*r^3

V=\frac{4}{3}\pi*(7x10^{-15})^3

V=2.932x10^{-14} m^3

P=\frac{82C}{2.932x10^{-14}m^3}=2.7965x10^{15} \frac{C}{m^3}

So replacing

∈=\frac{2.7965x10^{15}\frac{C}{m^3}}{8.8542x10^{-12}\frac{C^2}{N*m^2}}

∈=3.1584x10^{26} \frac{V}{m}

3 0
3 years ago
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