For what value(s) of k will each relation will not be a function? A={(k^2,16),(4k,32)}
1 answer:
Answer:
12x+4x-7y+45b+78a-44b+1a+1z+0d+1.1a+1.1a
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Answer:
C) Octagon
Step-by-step explanation:
option (C)
Answer:
g(3)=9-7=2
f(2)=5×2-4=10-4=6
Answer:
the last one?
Step-by-step explanation:
i dont know, but that one seems like it would
The answer is 2 because 4/1 - 83628 = four
