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mestny [16]
3 years ago
12

(a) How much gravitational potential energy (relative to the ground on which it is built) is stored in the Great Pyramid of Cheo

ps, given that its mass is about 7×109kg and its center of mass is 36.5 m above the surrounding ground? (b) How does this energy compare with the daily food intake of a person? [assuming that one regular calorie is 4.184 J and that a person’s daily food intake is 2,500 food calories – note a food calorie is 1,000 regular calories]
Physics
1 answer:
Nutka1998 [239]3 years ago
3 0

Answer:

(a) PE = 2.503 * 10^{12} J

(b) The gravitational energy stored in the Great Pyramid of Cheops is 2.38 * 10^5 times greater than the daily food intake of a person (in Joules).

Explanation:

(a) Gravitational potential energy (with respect to the earth) is the energy possessed by an object due to its position from the surface of the earth.

It is given as:

PE = mgh

where m = mass of object

g = acceleration due to gravity

h = height above the ground

∴ PE = 7 *10^9 * 9.8 * 36.5\\\\\\PE = 2.503 * 10^{12} J

(b) A person's daily food intake = 2500 food calories

1 food calorie = 1000 regular calories

∴ 2500 food calories = 2500 * 1000 regular calories = 2500000 regular calories

We are given that :

1 regular calorie = 4.184 J

∴ 2500000 regular calories = 2500000 * 4.184 J = 1.05 * 10^7 J

Comparing this with the answer in (a) above:

\frac{2.503 * 10^{12} J}{1.05 * 10^7 J}\\\\\\\frac{2.38 * 10^5}{1}\\ \\\\2.38 * 10^5 : 1

The gravitational energy stored in the Great Pyramid of Cheops is 2.38 * 10^5 times greater than the daily food intake of a person (in Joules).

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