Answer:
Explanation:
An object in free fall, NOT experiencing parabolic motion, has an equation of
which says:
The height of an object with respect to time in seconds is equal to the pull of gravity times time-squared plus the height from which it was dropped. Normally we use -9.8 for gravity but you said to use 10, so be it.
For us, h(t) is 5 because we are looking for the height of the window when the object is 5 m off the ground at .5 seconds;
g = 10 m/s/s, and
t = .5sec
+h and
5 = -5(.5)² + h and
5 = -5(.25) + h and
5 = -1.25 + h so
h = 6.25
That's how high the window is above the ground.
Answer:
1.25 m
Explanation:
From the question given above, the following data were obtained:
Force ratio = 2.5
Distance of load from the fulcrum = 0.5 m
Distance of effort =.?
The distance of the effort from the fulcrum can be obtained as illustrated below:
Force ratio = Distance of effort / Distance of load
2.5 = Distance of effort / 0.5
Cross multiply
Distance of effort = 2.5 × 0.5
Distance of effort = 1.25 m
Therefore, the distance of the effort from the fulcrum is 1.25 m
The answer to what experimental result required considering the particle nature of light is A. The ultraviolet catastrophe of blackbody radiation.
Answer:
Explanation:
A
35 N Small Dog <=======BONE=========> Bigger Dog 42 N
B
Fnet = Large Dog - small dog The forces are subtracted because they are acting in opposite Directions.
Fnet = 42 - 35
Fnet = 7 N
C
m = 2.5 kg
F = 7 N
a = ?
F = m * a
7 = 2.5 a
a = 7 / 2.5
a = 2.8 m/s^2
