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marin [14]
3 years ago
8

In which case is there an induced electromotive force?

Physics
2 answers:
Papessa [141]3 years ago
4 0
I think it's B, that's the only case where something is moving. I'm actually doing the quiz right now lol
wariber [46]3 years ago
4 0
<span>An electromagnet operating on alternating current is held inside a second coil of wire. (C)
I just took this test. That is the answer.</span>
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What is the rate of vibration measured in
jek_recluse [69]

Answer:

I'm not 100% sure tbh but the only thing I think makes sense to represent vibration would be frequency which is measure in Hertz (Hz)

Explanation:

7 0
3 years ago
Read 2 more answers
A force of 30.0 N is applied to a 3.00 kg object for 3.00 seconds. Calculate the velocity experienced by the object.
olganol [36]

Answer:

Explanation:

F = ma and

a=\frac{v}{t}

We have F, we have m, but in order to solve for v, we need a.

30.0 = 3.00a so

a = 10.0 m/s/s. Plug that in for a in the second equation and solve for v:

10.0=\frac{v}{3.00} so

v = 10.0(3.00) so

v = 30.0 m/s

6 0
2 years ago
Which winds are affected by specific landforms on earth's surface?
Blababa [14]
Hello!

The winds affected by specific landforms on earth's surface are: Local winds.

I hope my answer helped you out! :)

4 0
3 years ago
A proton moves at a constant velocity of 50m/s along the x axis ,through crossed electric and magnetic fields .The magnetic fiel
shusha [124]

Answer:

42 I THE CORRECT ANSWER

Explanation:

BECAUSE I KNOW

6 0
3 years ago
The diameter of an atom is 1.1×10−10m and the diameter of its nucleus is 1.0×10−14m. Part A What percent of the atom's volume is
77julia77 [94]

To solve this problem we will use the basic concept given by the Volume of a sphere with which the atom approaches. The fraction in percentage terms would be given by the division of the total volume of the nucleus by that of the volume of the atom, that is,

\% Percent = \frac{V_{nucleus}}{V_{atom}}*100

\% Percent = \frac{4/3 \pi (d_{nucleus}/2)^3}{4/3 \pi (d_{atom}/2)^3}*100

\% Percent = \frac{(d_{nucleus}/2)^3}{ (d_{atom}/2)^3}*100

\% Percent =\frac{(1.0*10^{-14}/2)^3}{ (1.1*10^{-10}/2)^3}*100

\% Percent = 7.51*10^{-13}*100

\% Percent = 7.51*10^{-11}\%

Therefore the percent of the atom's volume is occupied by mass is 7.51*10^{-11}\%

3 0
3 years ago
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