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levacccp [35]
3 years ago
12

When low on gasoline, is it better to increase or decrease the speed of the vehicle? Explain.

Physics
1 answer:
sergiy2304 [10]3 years ago
5 0
Yeah!! It is better to decrease the speed of the vehicle so the ejection of gases would happen in slow manner.... then you can save your gasoline
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o illustrate the work-energy concept, consider the case of a stone falling from xi to xf under the influence of gravity. Using t
Phantasy [73]

Answer: force of gravity on the body due to height difference above the earth's surface

Explanation: as you increase the height of a body above ground, you do work against gravity in moving it from a point on the earth's surface to that point. So a body falling has a stored up gravito-potential energy which acts on it downward due to its mass, accelerating it downwards

Answer b): kinetic energy of the body

Explanation: the downward force produces an acceleration of magnitude 9.81m/s2 downwards which means an increasing velocity. This increasing velocity means the kinetic energy of the body is increasing (kinetic energy is proportional to velocity of the body squared)

5 0
3 years ago
Consider a uniform solid sphere of radius R and mass M rolling without slipping. Which form of its kinetic energy is larger, tra
castortr0y [4]

Answer:

A. Its translational kinetic energy is larger than its rotational kinetic energy.

Explanation:

Given that

Radius = R

Mass = M

We know that mass moment of inertia for the solid sphere

I=\dfrac{2}{5}MR^2

Lets take angular speed =ω

Linear speed =V

Condition for pure rolling , V= ω R

Rotation energy ,RE

RE=\dfrac{1}{2}I\omega^2

RE=\dfrac{1}{2}\times \dfrac{2}{5}MR^2\times \omega^2

RE=\dfrac{1}{2}\times \dfrac{2}{5}MR^2\times \omega^2

RE=\dfrac{1}{5}\times MR^2\times \omega^2

RE=\dfrac{1}{5}\times MV^2

RE= 0.2  MV²

The transnational kinetic energy TE

TE=\dfrac{1}{2}MV^2

TE= 0.5 MV²

From above we can say that transnational energy is more than rotational energy.

Therefore the answer is A.

3 0
3 years ago
Maximum current problem. If the current on your power supply exceeds 500 mA it can damage the supply. Suppose the supply is set
VikaD [51]

To solve this problem we will apply Ohm's law. The law establishes that the potential difference V that we apply between the ends of a given conductor is proportional to the intensity of the current I flowing through the said conductor. Ohm completed the law by introducing the notion of electrical resistance R. Mathematically it can be described as

V = IR \rightarrow R = \frac{V}{I}

Our values are

I = 500mA = 0.5A

V = 37V

Replacing,

R = \frac{V}{I}

R = \frac{37}{0.5}

R = 74 \Omega

Therefore the smallest resistance you can measure is 74 \Omega

8 0
3 years ago
Which of the following is equivalent to 4.5 m?
Romashka [77]
We can’t see the following
3 0
3 years ago
Sound will travel slowest through which medium?
xxMikexx [17]
Ice at -25
Hope this helps
May God bless you and your family
8 0
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