Explanation:
a) <em>Fixed points</em> are the temperatures at which a thermometer is calibrated. They can refer either to the actual temperatures used for calibration, or the thermometer readings at those temperatures.
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b) <em>Fundamental interval</em> is the difference between the fixed points. As with fixed points, it can refer either to the difference in actual temperature, or the difference in the corresponding thermometer readings.
Answer:
The total amount after 3 years is = $ 2054.10
Explanation:
Given data
Principal Amount (P) = $ 1800
Rate of interest (R) = 4.5 %
Thus the total amount after 3 years compounded annually is given by the formula = P × ![[1 +\frac{R}{100} ]^{3}](https://tex.z-dn.net/?f=%5B1%20%2B%5Cfrac%7BR%7D%7B100%7D%20%20%5D%5E%7B3%7D)
⇒ 1800 × ![[1 +\frac{4.5}{100} ]^{3}](https://tex.z-dn.net/?f=%5B1%20%2B%5Cfrac%7B4.5%7D%7B100%7D%20%20%5D%5E%7B3%7D)
⇒ 2054.10
Thus the total amount after 3 years is = $ 2054.10
Compound interest earned in three years = 2054.10 - 1800 = $ 254.10
Answer:
A black hole is a region of space having a gravitational field so intense that no matter or radiation can escape.
Explanation:
Sorry if this isn't what you meant or were looking for.
Answer:
The answer is 1.87nm/s.
Explanation:
The
water loss must be replaced by
of sap. 110g of sap corresponds to a volume of

thus rate of sap replacement is

The volume of sap in the vessel of length
is
,
where
is the cross sectional area of the vessel.
For 2000 such vessels, the volume is

taking the derivative of both sides we get:

on the left-hand-side
is the velocity
of the sap, and on right-hand-side
; therefore,

and since the cross-sectional area is
;
therefore,

solving for
we get:


which is the upward speed of the sap in each vessel.
Answer:
Oprion A
The length of time over which the conditions are measured
Explanation:
Weather captures the daily atmospheric conditions over a short duration hence it is short-term. Climate is the average of weather and covers a longer duration hence long-term. Therefore, what differentiatea these two is the length of time over which the conditions are measured.