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Darina [25.2K]
3 years ago
14

Two sound waves W1 and W2, of the same wavelength interfere destructively at point P. The waves originate from two in phase spea

kers. W1 travels 36m and W2 travels 24m before reaching point P. Which of the following values could be the wave length of the sound waves?
a. 24m
b. 12m
c. 6m
d. 4m
Physics
1 answer:
dimaraw [331]3 years ago
8 0

Answer:

<em>a. 24 m</em>

<em></em>

Explanation:

Destructive interference occurs when two waves arrive at a point, out of phase. In a completely destructive interference, the two waves cancel out, but in a partially destructive interference, they produce a wave with a time varying amplitude, but maintain a wavelength the wavelength of one of the original waves. Since the two waves does not undergo complete destructive interference, then the possible value of the new wave formed can only be 24 m, from the options given.

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Presently, the speed of light in a vacuum is defined to be exactly 299,792,458 m/s (approximately 186,282 miles per second). . An early experiment to measure the speed of light was conducted by Ole Romer, a Danish physicist, in 1676. Using a telescope, Ole observed the motions of Jupiter and one of its moons, Io
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In most compartment fires, the energy release in fire is directly proportional to the:
Liula [17]

In most compartment fires, the energy release in fire is directly proportional to the amount of oxygen available for combustion.

Answer: Option B

<u>Explanation:</u>

A fire is the chemical outcome of energy generated by the heat. So, this heat is generating fire due to friction between the heating source with igniting elements. And to increase the chain reaction of fire leading to combustion or fire require oxygen. So, the amount of oxygen will lead to the production of fire. Thus, the energy released by fire will be equal to the amount of oxygen available for combustion.

If there is no oxygen, then the fire will get succumbed. The fire consumes the oxygen present to increase the pace and spread of fire. So the consumed oxygen utilized for converting the simple fire to combustion will be equal to the release of energy in fire. Thus, energy released in fire is directly proportional to the amount of oxygen available for combustion.

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4 years ago
A 67 Vrms source is placed across a load that consists of a 12 ohm resistor in series with an capacitor whose reactance is 5 ohm
SVETLANKA909090 [29]

a) The average true power is 318.3 W

b) The reactive power is 132.6 W

c) The apparent power is 344.8 W

d) The power factor is 0.92

Explanation:

a)

For a circuit made of a resistor and a capacitor, the average (true) power is given by the resistive part of the circuit only.

Therefore, the average true power is given by:

P=I^2R

where

I is the current

R is the resistance

In this problem, we have

V = 67 V (rms voltage)

R=12 \Omega is the resistance of the load

X=5\Omega is the reactance of the circuit

First we have to find the impedance of the circuit:

Z=\sqrt{R^2+X^2}=\sqrt{12^2+5^2}=13 \Omega

Then we can find the current in the circuit by using Ohm's law:

I=\frac{V}{Z}=\frac{67}{13}=5.15 A

Therefore, the average true power is

P=I^2R=(5.15)^2(12)=318.3 W

b)

The reactive power of a circuit consisting of a resistor and a capacitor is the power given by the capacitive part of the circuit.

Therefore, it is given by

Q=I^2X

where

I is the current

X is the reactance of the circuit

In this circuit, we have

I=5.15 A (current)

X=5 \Omega (reactance)

Therefore, the reactive power is

Q=(5.15)^2(5)=132.6W

c)

In a circuit with a resistor and a capacitor, the apparent power is given by both the resistive and capacitive part of the circuit.

Therefore, it is given by

S=I^2Z

where

I is the current

Z is the impedance of the circuit

Here we have

I = 5.15 A (current)

Z=13 \Omega (impedance)

Therefore, the apparent power is

S=I^2 Z=(5.15)^2(13)=344.8 W

d)

For a circuit with a resistor and a capacitor, the power factor is the ratio between the true power and the apparent power. Mathematically:

PF=\frac{P}{S}

where

P is the true power

S is the apparent power

For this circuit, we have

P = 318.3 W (true power)

S = 344.8 W (apparent power)

So, the power factor is

PF=\frac{318.3}{344.8}=0.92

Learn more about power and circuits:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

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Answer:

j

Explanation:

x = 4 t^2 - 2 t - 4.5

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a = dv / dt = 8

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alexandr1967 [171]

Answer:

Call a treatment service. Seek out a healthcare professional. Lastly, report the issue to the local authorities.

Why did I choose these?

You call the treatment services to take care of the person.

You seek out a healthcare professional to get him/her back in shape.

Then you report the issue so that nobody will be endangered by the person that is abusing alcohol. Many accidents occur because of this and that is why you report it.

Explanation:

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