By subtracting the value of absolute zero, also know as adding 273.15!
Answer:
2.57 seconds
Explanation:
The motion of the ball on the two axis is;
x(t) = Vo Cos θt
y(t) = h + Vo sin θt - 1/2gt²
Where; h is the initial height from which the ball was thrown.
Vo is the initial speed of the ball, 22 m/s , θ is the angle, 35° and g is the gravitational acceleration, 9.81 m/s²
We want to find the time t at which y(t) = h
Therefore;
y(t) = h + Vo sin θt - 1/2gt²
Whose solutions are, t = 0, at the beginning of the motion, and
t = 2 Vo sinθ/g
= (2 × 22 × sin 35°)/9.81
= 2.57 seconds
Answer:
Explanation:
We know that the electric force equation is:

- k is the electric constant

- r is the distance between the particles
- q1 and q2 are the particle
Now, we have three particles, the first one at x=0, the second one at x=2a and the third in some place between these two particle.
1. Let's find the electric force between the first particle and the third particle.



r(31) is the distance between 3 and 1
2. Now, let's find the electric force between the third particle and the second particle.



r(32) is the distance between 3 and 2.
Now,
or 
The net force must be zero so:
![F_{31}+F_{32}=0[\tex][tex]k\frac{2q^{2}}{r_{31}^{2}}-k\frac{q^{2}}{r_{32}^{2}}=0[\tex] [tex]kq^{2}(\frac{2}{r_{31}^{2}}-\frac{1}{r_{32}^{2}})=0[\tex] [tex]kq^{2}(\frac{2}{r_{31}^{2}}-\frac{1}{(2a-r_{31})^{2}})=0[\tex] It means that:[tex]\frac{2}{r_{31}^{2}}-\frac{1}{(2a-r_{31})^{2}}](https://tex.z-dn.net/?f=F_%7B31%7D%2BF_%7B32%7D%3D0%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3E%5Btex%5Dk%5Cfrac%7B2q%5E%7B2%7D%7D%7Br_%7B31%7D%5E%7B2%7D%7D-k%5Cfrac%7Bq%5E%7B2%7D%7D%7Br_%7B32%7D%5E%7B2%7D%7D%3D0%5B%5Ctex%5D%20%20%20%3C%2Fp%3E%3Cp%3E%5Btex%5Dkq%5E%7B2%7D%28%5Cfrac%7B2%7D%7Br_%7B31%7D%5E%7B2%7D%7D-%5Cfrac%7B1%7D%7Br_%7B32%7D%5E%7B2%7D%7D%29%3D0%5B%5Ctex%5D%20%3C%2Fp%3E%3Cp%3E%5Btex%5Dkq%5E%7B2%7D%28%5Cfrac%7B2%7D%7Br_%7B31%7D%5E%7B2%7D%7D-%5Cfrac%7B1%7D%7B%282a-r_%7B31%7D%29%5E%7B2%7D%7D%29%3D0%5B%5Ctex%5D%20%3C%2Fp%3E%3Cp%3EIt%20means%20that%3A%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cfrac%7B2%7D%7Br_%7B31%7D%5E%7B2%7D%7D-%5Cfrac%7B1%7D%7B%282a-r_%7B31%7D%29%5E%7B2%7D%7D)
We just need to solve it for r(31)


Therefore the distance from the origin will be:
I hope it helps you!
I believe the answer is C. It will maintain its state of motion
Answer:

Explanation:
The acceleration of an object is given by

where
v is the final velocity
u is the initial velocity
t is the time it takes for the velocity to change from u to v
For the boat in the problem,
v = 10 m/s
u = 0
t = 2 s
Substituting, we find the acceleration
