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4 years ago

What particle flows to produce electric current

Physics

1 answer:

alexandr402 [8]4 years ago

5 0

The particle that flows to produce an electric current is the electron (c)...GOOD LUCK!!!

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Which physical phenomenon causes the spherical shapes of raindrops

jeyben [28]

Answer:

Raindrops start to form in a roughly spherical structure due to the surface tension of water. This surface tension is the "skin" of a body of water that makes the molecules stick together. The cause is the weak hydrogen bonds that occur between water molecules.

6 0

3 years ago

You hold a 0.125 kg glider A and a 0.500 kg glider B at rest on an air track with a compressed spring of negligible mass between

o-na [289]

Answer:

Magnitude |VB| = 0.32 m/s

and

Direction is to the left

Explanation:

given data

glider A mass = 0.125 kg

glider B mass = 0.500 kg

glider A move = 0.960 m to the left

solution

we use here Conservation of momentum that is

M1 × U1 + M2 × U2 =M1 × V1 + M2 × V2 ........................1

put here value and we get

0.125 × 0 + 0.500 × 0 = 0.125 × 0.960 + 0.375 × VB

VB = −0.32 m/s

Magnitude |VB| = 0.32 m/s

and

Direction is to the left

8 0

3 years ago

A go cart starts from REST and accelerates uniformly over a time of 7 seconds for a distance of 100m. Determine the acceleration

Hunter-Best [27]

Answer:

please find attached pdf

Explanation:

Download pdf

6 0

3 years ago

A wheel has a constant angular acceleration of 1.8 rad/s2. During a certain 4.0 s interval, it turns through an angle of 45 rad.

tankabanditka [31]

Answer:

4.25 s

Explanation:

Given:

angular acceleration'α'= 1.8 rad/s²

angle 'θ'= 45 rad

time 't'= 4s

initial angular velocity ' $w_{o}$ '=0 $rad^{-1}$

as we know that,

θ= $w_{1}$ t + $\frac{1}{2} \alpha t^{2}$

45 = 4 $w_{1}$ + (0.5 x 1.8 x 16)

45- 14.4 = 4 $w_{1}$

30.6 = 4 $w_{1}$

$w_{1}$ = 7.65 $rad^{-1}$

Next is to find t by using the equation

$w_{1}$ = $w_{o}$ + $\alpha t_{1}$

7.65= 0 + (1.8) $t_{1}$

$t_{1}$ = 7.65/1.8

$t_{1}$ = 4.25 s

Therefore, At the start of 4s interval the motion is at 4.25 second

7 0

4 years ago

You have a 160-Ω resistor and a 0.430-H inductor. Suppose you take the resistor and inductor and make a series circuit with a vo

S_A_V [24]

Answer:

A. Z = 185.87Ω

B. I = 0.16A

C. V = 1mV

D. VL = 68.8V

E. Ф = 30.59°

Explanation:

A. The impedance of a RL circuit is given by the following formula:

$Z=\sqrt{R^2+\omega^2L^2}$ (1)

R: resistance of the circuit = 160-Ω

w: angular frequency = 220 rad/s

L: inductance of the circuit = 0.430H

You replace in the equation (1):

$Z=\sqrt{(160\Omega)^2+(220rad/s)^2(0.430H)^2}=185.87\Omega$

The impedance of the circuit is 185.87Ω

B. The current amplitude is:

$I=\frac{V}{Z}$ (2)

V: voltage amplitude = 30.0V

$I=\frac{30.0V}{185.87\Omega}=0.16A$

The current amplitude is 0.16A

C. The current I is the same for each component of the circuit. Then, the voltage in the resistor is:

$V=\frac{I}{R}=\frac{0.16A}{160\Omega}=1*10^{-3}V=1mV$ (3)

D. The voltage across the inductor is:

$V_L=L\frac{dI}{dt}=L\frac{d(Icos(\omega t))}{dt}=-LIsin(\omega t)\\\\V_L=-(0.430H)(160\Omega)sin(220 t)=68.8sin(220t)\\\\V_L_{max}=68.8V$

E. The phase difference is given by:

$\phi=tan^{-1}(\frac{\omega L}{R})=tan^{-1}(\frac{(220rad/s)(0.430H)}{160\Omega})\\\\\phi=30.59\°$

5 0

3 years ago