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Nonamiya [84]
3 years ago
8

Using the formula: w=xyz, find w when x=22, y=12. z=6

Mathematics
1 answer:
weeeeeb [17]3 years ago
8 0

Answer:

40

Step-by-step explanation:

If w = xyz then it will be:

<em>22</em><em> </em><em>+</em><em> </em><em>12</em><em> </em><em>+</em><em> </em><em>6</em><em> </em><em>=</em><em> </em><em>40</em>

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What is the answer to <br> 6x&gt; -54
Anestetic [448]

Answer:

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7 0
3 years ago
Which statement describes the inverse of m(x) = x^2 – 17x?
DochEvi [55]

Given:

The function is

m(x)=x^2-17x

To find:

The inverse of the given function.

Solution:

We have,

m(x)=x^2-17x

Substitute m(x)=y.

y=x^2-17x

Interchange x and y.

x=y^2-17y

Add square of half of coefficient of y , i.e., \left(\dfrac{-17}{2}\right)^2 on both sides,

x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2        [\because (a-b)^2=a^2-2ab+b^2]

Taking square root on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}

Add \dfrac{17}{2} on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y

Substitute y=m^{-1}(x).

m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}

We know that, negative term inside the root is not real number. So,

x+\left(\dfrac{17}{2}\right)^2\geq 0

x\geq -\left(\dfrac{17}{2}\right)^2

Therefore, the restricted domain is x\geq -\left(\dfrac{17}{2}\right)^2 and the inverse function is m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}.

Hence, option D is correct.

Note: In all the options square of \dfrac{17}{2} is missing in restricted domain.

7 0
3 years ago
Help please?!?!?!?!?!?!
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8 0
3 years ago
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mariarad [96]
I think the answer is 180 since 360/2=180
3 0
3 years ago
A circle has a diameter of 20 inches and a central angle AOB that measures 160°. What is the length of the intercepted arc AB? U
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divide 160 by 360 (full circle) and multiply by the circumference:

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5 0
3 years ago
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