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3 years ago

Using the formula: w=xyz, find w when x=22, y=12. z=6

Mathematics

1 answer:

weeeeeb [17]3 years ago

8 0

Answer:

Step-by-step explanation:

If w = xyz then it will be:

22 + 12 + 6 = 40

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How many solutions y=x^2-10x+25

MrRissso [65]

<h2>There are infinite solution of y.</h2>

Step-by-step explanation:

Given,

y = $x^2$ - 10x + 25

To find, the total number of solutions = ?

∴ y = $x^2$ - 10x + 25

⇒ y = $x^2$ - 2(x)(5) + $5^2$

⇒ y = $(x-5)^{2}$

There are infinite solution of y.

Thus, there are infinite solution of y.

7 0

3 years ago

Solve for x. 4 | x - 7 | + 2 | x - 7 | = 12

miv72 [106K]

Answer: x = 9, 5

Step-by-step explanation:

4 | x - 7 | + 2 | x - 7 | = 12

6 | x - 7 | = 12 added like terms

| x - 7 | = 2 divided both sides by 6

x - 7 = 2 or x - 7 = -2 removed absolute value sign

x = 9 or x = 5 added 7 to both sides of both equations

7 0

3 years ago

PLEASE HELP ASAP ITS TIMED

strojnjashka [21]

Answer:

D. x<-9

Step-by-step explanation:

-3(x+5)>12

x+5<12/-3

x+5<-4

x<-4-5

x<-9

7 0

3 years ago

The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of

ivanzaharov [21]

<h2>Answer:</h2>

$R_2$ is 3 ohms

<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors $R_1$ and $R_2$ connected together in parallel, the total resistance $R_T$ is given by;

$\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}$ ---------(i)

Make $R_2$ subject of the formula;

=> $\frac{1}{R_2} = \frac{1}{R_T} - \frac{1}{R_1}$

=> $\frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}$

=> ${R_2} = \frac{R_TR_1}{R_1 - R_T}$ ---------------(ii)

From the question,

$R_1$ = 6Ω

$R_T$ = 2Ω

Substitute these values into equation (ii) as follows;

=> ${R_2} = \frac{2*6}{6 - 2}$

${R_2} = \frac{12}{4}$

$R_2$ = 3Ω

Therefore, the value of $R_2$ = 3 ohms or $R_2$ = 3Ω

3 0

3 years ago

M,H, and G have written more than a combined total of 22 articles. H has written 1/4 as many as M. G has written 3/2 as M. Write

Natalka [10]

Missing part of the question:

Write an inequality to determine the number of articles, M could have written for the school newspaper.

Answer:

The inequality: $11M > 88$

The solution: $M > 8$

Step-by-step explanation:

Given

From the question, we have the following parameters:

$M + H + G > 22$

$H = \frac{1}{4}M$

$G = \frac{3}{2}M$

Required

Determine the inequality to solve for M

Substitute the values for H and G in the inequality:

$M + H + G > 22$

$M + \frac{1}{4}M + \frac{3}{2}M > 22$

Multiply through by 4

$4(M + \frac{1}{4}M + \frac{3}{2}M) > 22*4$

$4M + M + 6M > 88$

$11M > 88$

Divide both sides by 11

$M > 8$

4 0

3 years ago