Answer:
65
Step-by-step explanation:
I dont know the answer hope this helps
Take the homogeneous part and find the roots to the characteristic equation:

This means the characteristic solution is

.
Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form

. Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.
With

and

, you're looking for a particular solution of the form

. The functions

satisfy


where

is the Wronskian determinant of the two characteristic solutions.

So you have




So you end up with a solution

but since

is already accounted for in the characteristic solution, the particular solution is then

so that the general solution is
a equals 16. You multiply both sides be -10 and then you add 6.
3/5*3
pretend that 3 has a denominator which is 1
3/5*3/1
mutiply the numerators together
3*3= 9
mutiply the denominators together
5*1= 5
Answer:
9/5, 1.8 and 1 4/5
<span>a regular hexagon inscribed in a circle </span>