All categories

3 years ago

The movement of a magnetic pole away from the actual pole

1 answer:

3 0

The North Magnetic Pole is the point on the surface of Earth's Northern Hemisphere at which the planet's magnetic field points vertically downwards (in other words, if a magnetic compass needle is allowed to rotate about a horizontal axis, it will point straight down). There is only one location where this occurs, near (but distinct from) the Geographic North Pole and the Geomagnetic North Pole.

You might be interested in

An astronaut's training centrifuge has a radius of 4.0m. If it goes round once every 2.5s, calculate the velocity of the end of

alexandr1967 [171]

Answer: 10.048m/s

Explanation:

We know that the radius is r = 4.0m

And for rotating things, the tangential velocity (or the velocity of the end of the centrifuge arm) can be calculated as:

v = r*w

The period is T = 2.5s,

This means that if sin(w*t) describes this situation, we have that:

sin(w*t) = sin(w*(t + T))

and we know that:

sin(w*0) = 0

sin(w*(0 + T)) = Sin(w*T) = 0

this means that w*T = 2*pi

w = 2*pi/T = 2*pi/2.5s = (2*3.14)/2.5 s = 2.512 hz

Then the velocity can be calculated as

v = r*w = 4.0m*2.512hz = 10.048m/s

6 0

2 years ago

How many times does the world go around

sattari [20]

I'm not sure what you're asking but the earth has the ability to infinitely continue to spin or the earth completes 365.25 rotations during a full cycle.

6 0

2 years ago

How many mL are in a cubic centimeter?

Furkat [3]

None of the above. 1 mL= 1 cubic centimeter
mm is the smallest.

4 0

3 years ago

Read 2 more answers

Please help me with questions 1, 2 and 3. <br> i need a step by step explanation

kifflom [539]

Answer:

1) d

2) 5 m/s

3) 100

Explanation:

The equation of position x for a constant acceleration a and an initial velocity v₀, initial position x₀, time t is:

(i) $x=\frac{1}{2}at^2+v_0t+x_0$

The equation for velocity v and a constant acceleration a is:

(ii) $v=at+v_0$

1) Solve equation (ii) for acceleration a and plug the result in equation (i)

(iii) $a = \frac{v -v_0}{t}$

(iv) $x = \frac{v-v_0}{2t}t^2+v_0t + x_0$

Simplify equation (iv) and use the given values v = 0, x₀ = 0:

(v) $x=-\frac{v_0}{2}t + v_0t= \frac{v_0}{2}t$

2) Given v₀= 3m/s, a=0.2m/s², t=10 s. Using equation (ii) to get the final velocity v: $v=at+v_0=0.2\frac{m}{s^2} * 10s+3\frac{m}{s}=2\frac{m}{s}+3\frac{m}{s}=5\frac{m}{s}$

3) Given v₀=0m/s, t₁=10s, t₂=1s and x₀=0. Looking for factor f = x(t₁)/x(t₂) using equation(i) to calculate x(t₁) and x(t₂):

$f=\frac{x(t_1)}{x(t_2)}=\frac{\frac{1}{2}at_1^2 }{\frac{1}{2}at_2^2}=\frac{t_1^2}{t_2^2}=\frac{10^2}{1^2}=\frac{100}{1}$

5 0

3 years ago

Es frecuente que en las instalaciones eléctricas domésticas se utilice alambre de cobre de 2.05 mm de diámetro. Determine la res

Tasya [4]

Answer:

The resistance is 0.124 ohm.

Explanation:

It is common for domestic electrical installations to use copper wire with a diameter of 2.05 mm. Determine the resistance of such a wire with a length of 24.0 m.

diameter, d = 2.05 mm

radius, r = 1.025 mm

Length, L = 24 m

resistivity of copper = 1.7 x 10^-8 ohm m

Let the resistance is R.

$R =\rho \frac{L}{A}\\\\R = \frac {1.7\times10^{-8}\times 24}{3.14\times1.025\times1.025\times 10^{-6}}\\\\R = 0.124 ohm$

7 0

2 years ago