The magnitude of the cannonball's velocity after 1.23 s will be 59.46 m/sec.
<h3>What is velocity?</h3>The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is
u is the initial velocity of canonball= 47.4 m/sec
g is the acceleration of free fall = 9.81 m/sec²
v is the velocity after 1.23 s
According to Newton's first equation of motion,
Hence, the magnitude of the cannonball's velocity after 1.23 s will be 59.46 m/sec.
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Answer:
55 min
Explanation:
The missing question is: how long does the trip take?
First of all, we need to find the initial distance covered by Dylan. In the first part, he rides for
at a speed of
v = 15 mph
therefore, the distance he covered is
Then Dylan stopped for a time of
Finally, on the way back, Dylan covered again this distance but travelling at a new speed of
v = 10 mph
So, the time he took is
So, the total time of the trip was
(a)
Electronic configuration is given as follows:
Since, this is the electronic configuration of ion with+3 that means 3 electrons are removed. On adding the 3 electrons, the electronic configuration of neutral atom can be obtained.
Thus, electronic configuration of neutral atom is .
The atomic number of Kr is 36, thus, total number of electrons become 36+6=42.
This corresponds to element: molybdenum. Thus, the tripositive atom will be .
(b) The given electronic configuration is .
The atomic number of Kr is 36, thus, total number of electrons become 36+4=40.
This corresponds to element zirconium, represented by symbol Zr.