Is this an addition problem?
Answer:
24.525 g of sulfuric acid.
Explanation:
Hello,
Normality (units of eq/L) is defined as:
Since the sulfuric acid is the solute, and we already have the volume of the solution (500 mL) but we need it in liters (0.5 L, just divide into 1000), the equivalent grams of solute are given by:
Now, since the sulfuric acid is diprotic (2 hydrogen atoms in its formula) 1 mole of sulfuric acid has 2 equivalent grams of sulfuric acid, so the mole-mass relationship is developed to find its required mass as follows:
Best regards.
Answer : The atomic mass of chlorine is, 36.723 amu
Explanation :
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
As we are given that,
Mass of 35-Cl isotope = 35 amu
Percentage abundance of 35-Cl isotope = 13.85 %
Fractional abundance of 35-Cl isotope = 0.1385
Mass of 37-Cl isotope = 37 amu
Percentage abundance of 37-Cl isotope = 86.15 %
Fractional abundance of 37-Cl isotope = 0.8615
Now put all the given values in above formula, we get:
Therefore, the atomic mass of chlorine is, 36.723 amu
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<span>Zinc, Copper,and Iron are elements
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