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Scorpion4ik [409]
3 years ago
15

Water waves are surface waves. The energy of the waves moves

Chemistry
2 answers:
horrorfan [7]3 years ago
8 0

Answer:

Explanation:

<em>Waves are actually energy passing through the water, causing it to move in a circular motion. ... This phenomenon is a result of the wave's orbital motion being disturbed by the seafloor.</em>

<em />

<em>The direction a wave propagates is perpendicular to the direction it oscillates for transverse waves. A wave does not move mass in the direction of propagation; it transfers energy.</em>

Dominik [7]3 years ago
4 0
Only perpendicular to the waves
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Given information : H = -92 KJ/mol and S = -0.199 KJ/(mol.K)

At equilibrium G = 0

We have to find the Temperature at which reaction would be spontaneous.

For spontaneous reaction : \triangle G = negative (-)

For non-spontaneous reaction : \triangle G = positive (+)

We can find the temperature using the formula for Gibbs free energy which is:

\triangle G = \bigtriangleup H - T\bigtriangleup S

Where, G = Gibbs free energy ,

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S = Entropy

T = Temperature

By plugging the value of G , H and S in the above formula we can find 'T'

\triangle G = \bigtriangleup H - T\bigtriangleup S

Since reaction should be spontaneous that means \triangle G should be negative , so the above formula can be written as :

\triangle G < \bigtriangleup H - T\bigtriangleup S

On rearranging the above formula we get :

0 < \bigtriangleup H - T\bigtriangleup S

T < \frac{\bigtriangleup H}{\bigtriangleup S}

T < \frac{-92\frac{KJ}{mol}}{-0.199\frac{KJ}{mol.K}}

T < (\frac{-92}{-0.199})\times (\frac{KJ}{mol})\times (\frac{mol.K}{KJ})

T < 462.3 K

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