Answer:
47.43 m/s
Explanation:
Given that,
Final speed of a plane, v = 0
Distance, d = 180 m
Acceleration of the plane, a = -6.25 m/s² (deceleration )
We need to find the plane's velocity. Let it was u. So, using the third equation of kinematics as :
So, the plane's velocity when it first touched the landing strip is 47.43 m/s.
Answer:
Deceleration of 0.075m/s²
Explanation:
Given parameters:
Initial velocity = 5m/s
Time = 40s
Final velocity = 2m/s
Unknown:
The jogger's acceleration = ?
Solution:
To solve this problem, we use;
a =
a is the acceleration
v is the final velocity
u is the initial velocity
t is the time taken
a = = - 0.075m/s²