All categories

4 years ago

If there is no pressure, water will ?

Chemistry

1 answer:

kvv77 [185]4 years ago

6 0

Here we have to choose the correct statement on the condition of water if there is no pressure.

At zero or absence pressure the water molecule remains in gaseous form only.

If the pressure is zero then the volume will be maximum as per the Boyle's law.

The change of state of a compound from gas to liquid is depend upon the probable inter-molecular interaction between the molecules. In water there remains hydrogen bond which is absent in its gaseous form (water vapor), moderately strong in liquid form (water) and highly strong in solid form (ice).

If there will be more pressure the molecules will forced to come close to each other and the possible hydrogen bond will form which will lead to the state of the water from gaseous to liquid.

However in the gaseous form the rate of movement of any molecule will be high than the liquid form.

The pressure is inversely proportional to the temperature by the Charles' law Thus if there is no pressure there will be high temperature.

Thus if there will be no pressure, water molecules will change to gas.

You might be interested in

What is the name of Earth's closest star? Question 1 options: Sirrius Achemar Sun Canopus

GenaCL600 [577]

Answer:

Sun

Explanation:

The closest star from the Earth is the sun.

7 0

4 years ago

Who is boo johnson ??

matrenka [14]

a skate border? i think ?

7 0

3 years ago

Read 2 more answers

One kilogram of water at 100 0C is cooled reversibly to 15 0C. Compute the change in entropy. Specific heat of water is 4190 J/K

mina [271]

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy ( $s_{2} - s_{1}$ ), in joules per gram-Kelvin, by the following model:

$s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }$

$s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }$

$s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}}$ (1)

Where:

$m$ - Mass, in kilograms.

$c_{w}$ - Specific heat of water, in joules per kilogram-Kelvin.

$T_{1}$ , $T_{2}$ - Initial and final temperatures of water, in Kelvin.

If we know that $m = 1\,kg$ , $c_{w} = 4190\,\frac{J}{kg\cdot K}$ , $T_{1} = 373.15\,K$ and $T_{2} = 288.15\,K$ , then the change in entropy for the entire process is:

$s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}$

$s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}$

The change in entropy is -1083.112 joules per kilogram-Kelvin.

7 0

3 years ago

How many grams of Br are in 445 g CaBr2 ?

aliya0001 [1]

Explanation:

The mass of bromine is 79.904, and since there are two of them in the Calcium Bromide molecule, we'll multiply it by 2 to get 159.808. Dividing that by the full mass of the molecule then multiply it by 100 will give you the answer.

8 0

3 years ago

Which area should have the lowest temperatures? A. 1 B.2 C.3 D.4

pochemuha

Answer:

A. 1

Explanation:

The higher you get in the atmosphere the cooler the temperature will be. The reason it's actually colder is because, as you go up in the atmosphere, the Earth's atmosphere feels less pressure the higher up you go. So as the gas in the atmosphere rises it feels less pressure, which makes it expand.

Hope this Help :)

Please mark brainliest :D

7 0

3 years ago