Answer:
I would say the answer is b.
Explanation:
Answer:
The correct answer is option B.
Explanation:
As given ,that 30.24 mL of base was neutralize by 86.14 mL of acid which means that moles of base present in 30.24 mL are neutralized by moles of acid present in 86.14 mL.
After dilution of base from 30.24 mL to 50.0 mL .Since, the moles of base are same in the solution as that of the moles in solution before dilution. Moles of acid require to neutralize the base after dilution will same as a that of present moles of acid present in 86.14 mL.
The rate of a reaction would be one-fourth.
<h3>Further explanation</h3>
Given
Rate law-r₁ = k [NO]²[H2]
Required
The rate of a reaction
Solution
The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.
Can be formulated:
Reaction: aA ---> bB
![\large{\boxed{\boxed{\bold{v~=~-\frac{\Delta A}{\Delta t}}}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Cboxed%7B%5Cboxed%7B%5Cbold%7Bv~%3D~-%5Cfrac%7B%5CDelta%20A%7D%7B%5CDelta%20t%7D%7D%7D%7D)
or
![\large{\boxed{\boxed{\bold{v~=~+\frac{\Delta B}{\Delta t}}}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Cboxed%7B%5Cboxed%7B%5Cbold%7Bv~%3D~%2B%5Cfrac%7B%5CDelta%20B%7D%7B%5CDelta%20t%7D%7D%7D%7D)
The concentration of NO were halved, so the rate :
![\tt r_2=k[\dfrac{1}{2}No]^2[H_2]\\\\r_2=\dfrac{1}{4}k.[No]^2[H_2]\\\\r_2=\dfrac{1}{4}r_1](https://tex.z-dn.net/?f=%5Ctt%20r_2%3Dk%5B%5Cdfrac%7B1%7D%7B2%7DNo%5D%5E2%5BH_2%5D%5C%5C%5C%5Cr_2%3D%5Cdfrac%7B1%7D%7B4%7Dk.%5BNo%5D%5E2%5BH_2%5D%5C%5C%5C%5Cr_2%3D%5Cdfrac%7B1%7D%7B4%7Dr_1)
I think the answer would be yes. if my math is correct 84,596 divided by 29 equals 2,917 sickles. 2,917 sickles is equal to 172 galleon. therefore he would have enough to buy the 70 galleon broomstick. hopefully i did this right and it helped!
A box and a laptop are both examples of solids
hope i helped:)