All categories

2 years ago

Help me to factorise the following expressions1.tu+tv+su+sv2.mn+3m+kn+3k

Mathematics

1 answer:

ioda2 years ago

4 0

Answer:

1. (t + s)(u + v).

2. (m + k)(n + 3).

Step-by-step explanation:

1. tu+tv+su+sv

Note that t is common in the first 2 terms and s is common to the last 2.

= t(u + v) + s(u + v)

Now u + v is common so we have:

(t + s)(u + v).

2. mn+3m+kn+3k

= m(n + 3) + k(n + 3)

= (m + k)(n + 3).

You might be interested in

Le regioni italiane bagnate dal mare sono un insieme?

arsen [322]

Answer:

non so cosa intendi per intero

Step-by-step explanation:

Può essere più preciso?

7 0

2 years ago

Jose is thinking of a number.

alexira [117]

The number is 66.

Solution:

Let the number be x.

To find the number x using given conditions.

Start with the last condition.

It is less than 7 times 8 + 23 = 7 × 8 + 23 = 79

So, the number is less than 79 which implies x < 79.

Using condition (4),

It is greater than 5 times 4 = 5 × 4 = 20

So, the number is greater than 79 which implies x > 20.

Combining condition (4) and (7), we get 20 < x < 79.

Using condition (3) and (5),

The number is a multiple of 11 and 6.

The number which is multiplied by both 11 and 6 is 66, 132, ...

But here x lies between 20 < x < 79.

So x = 66.

66 is not odd number and the sum of the digits is divisible by 2.

Therefore condition (1) and (2) also satisfied.

Hence the number is 66.

3 0

3 years ago

PLSS HELP I NEED IT RN

Kisachek [45]

Answer:

x >= -3

x is greater than or equal to -3

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

a crowbar of 2cm is used to lift an object if 800N. if the effort arm is 260cm. calculate the effort applied.

Gelneren [198K]

Answer:

solution:Here

Given,

Load=800 N

Load distance=2cm

Effort distance=260cm

Effort applied=?

We know that,

Load × Load distance = Effort × Effort distance

or, 800×2 = e × 260

or,1600 = 260e

or,e = 1600/260

Thus, e = 6.15 N

Hence, The effort applied = 6.15 N

Hope this answer helped you..

Please mark me as brainliest

8 0

6 months ago

The sum of the first 5 terms of an AP is 30 and the sum of the four term from T6 to T9 (inclusive) is 69. Find the AP

Ainat [17]

Answer: The AP = 1, ⁷/₂, 6, ¹⁷/₂, 11 ..............

Step-by-step explanation:

From the first statement,

S₅ = ⁵/₂(2a + ( n - 1 )d } = 30

5(2a + 4d )d = 60

10a + 20d = 60

reduce to lowest term to easy calculation by dividing through by 10

a + 2d = 6 -----------------------------------1

second statement

sum of the next 4 terms inclusive

T₉ = ⁹/₂(2a + 8d ) = 69

9(2a + 8d ) = 30 + 69

18a + 72d = 99 x 2

18a + 72d = 198

divide through by 18 to reduce to lowest time

a + 4d = 11 ------------------------------------------2

Now solve the two equation simultaneously to find a and d

a + 2d = 6

a + 4d = 11

-2d = -5

d = ⁵/₂.

Now substitute for d to get a

a + 2(⁵/₂) = 6

a + 5 = 6

a = 6 - 5

a = 1.

Therefore the AP = 1 , ⁷/₂ , 6 , ¹⁷/₂ , 11 , ..............

7 0

2 years ago

Help me to factorise the following expressions1.tu+tv+su+sv2.mn+3m+kn+3k​

Help me to factorise the following expressions1.tu+tv+su+sv2.mn+3m+kn+3k