Answers :
Explanation:
Given that.
First cylinder data
Inertial I₁ = 2.4 kgm²
angular speed ω₁ = 5.8 rad/s.
Second cylinder data
inertia I₂ = 1.3 kgm²
angular speed ω₂ = 7.0 rad/s.
If the cylinders couple so they have the same rotational axis, what is the angular speed of the combination (in rad/s)?
So, the cylinder couple and move together with the same angular speed
Then, using conservation of angular momentum
L(final) = L(initial)
(I₁ + I₂) • ω = I₁•ω₁ + I₂ω₂
(2.4+1.3)•ω = 2.4 × 5.8 + 1.3 × 7
3.7•ω = 23.02
ω = 23.02 / 3.7
ω = 6.22 rad/s
The combine angular speed of the cylinder is 6.22 rad/s
Answer:
Momentum is the product of the mass of an object times its <em>VELOCITY</em><em>.</em><em> </em>
<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>!</em><em>!</em><em> </em>
Answer:
a) -180.7 kN/C
b) -474.3 kN/C
c) 180.7 kN/C
Explanation:
For infinite planes the electric field is constant on each side, and has a value of:
E = σ / (2 * e0) (on each side of the plate the field points in a different direction, the fields point towards positive charges and away from negative charges)
The plate at -5 m produces a field of:
E1 = 2.6*10^-6 / (2 * 8.85*10^-12) = 146.8 kN/C into the plate
The plate at 3 m:
E2 = 5.8*10^-6 / (2 * 8.85*10^-12) = 327.5 kN/C away from the plate
At x < -5 m the point is at the left of both fields
The field would be E = 146.8 - 327.5 = -180.7 kN/C
At -5 m < x < 3 m, the point is between the plates
E = -146.8 - 327.5 = -474.3 kN/C
At x > 3 m, the point is at the right of both plates
E = -146.8 + 327.5 = 180.7 kN/C
Answer:
to the left
Explanation:
The gravitational force exerted between two objects is given by:
where
G is the gravitational constant
m1, m2 are the masses of the two objects
r is their separation
And the force is always attractive.
Let's call
the mass on which we are calculating the net force.
The mass on the left is
and it is a distance of
r = 0.500 m
So the gravitational force exerted by this mass on the 10.0 kg mass is
And the direction is to the left.
The other mass is
and its distance is
r = 1.25 m
to the right, so the force exerted by this other mass on the 10.0 kg mass is
And the direction is to the right.
Now, to find the net force, we just have to calculate the algebraic sum, taking into account that the two forces have different directions; taking right as positive direction, the net force is:
And the negative sign means the direction of the net force is to the left.