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Maru [420]
3 years ago
13

Once juno reaches jupiter, what is the minimum amount of time it takes for the transmitted signals to travel from the spacecraft

to earth?
Physics
2 answers:
arsen [322]3 years ago
5 0

speed of light = juno to earth/time

time= juno/3x10^8. if dist in metres answer is in seconds.

probably not long

Komok [63]3 years ago
4 0

In very very very round figures . . .

-- Jupiter is about 5.2 times as far from the sun as the earth is.

-- So when Jupiter and the EARTH are aligned in both orbits, Jupiter is about

(4.2) x (150 million kilometers) = 630 million kilometers

Time = (distance) / (speed)

The speed of light and radio is 300,000 km/second

Time = (630 million / 300 thousand)

<em>Time = 2,100 seconds</em>

That's 35 minutes.

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If you use a force of 90 N to pick up a 10 pound bag of charcoal, what is the acceleration?
hjlf

Answer:

9ms^2

Explanation:

since ,Force=mass*acceleration

then, acceleration=force/mass

and, Force=90N

Mass=10pound

therefore, acceleration=90/10

=9ms^2

8 0
3 years ago
An object is dropped from a height of 25 meters. At what velocity will it hit the ground?
Goryan [66]
You can use Vf^2-Vi^2 = 2ax

Vf^2 - 0 = 2(9.81)(25)

Or you can use energy

mgh = 1/2mv^2

2gh =v^2

Same thing
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2 years ago
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4 0
2 years ago
Read 2 more answers
A runner is jogging in a straight line at a
soldi70 [24.7K]

Answer:

13 km

Explanation:

The bird flies from the runner, to the finish line, and back to the runner.  We can write two equations for the distance it travels:

d = 7.8 km + 7.8 km − 4.9 km/hr × t

d = 24.5 km/hr × t

Solve for t in the second equation and substitute into the first:

t = d / 24.5

d = 7.8 + 7.8 − 4.9 (d / 24.5)

d = 15.6 − 0.2 d

1.2 d = 15.6

d = 13

The bird flies a cumulative distance of 13 km.

4 0
3 years ago
Calculate the work required to lift a 2000 kg vehicle on a lift, 2.0 m at constant speed, assuming friction averages 500 N..a. 3
hoa [83]

Answer:

c. 40200 J

Explanation:

Assume gravitational constant g = 9.8m/s2. The weight of the 2000kg vehicle is

W = mg = 2000*9.8 = 19600 N

In addition to the friction averaging at 500N, the total force is

F = 20000 + 500 = 20100 N

The work required to generate this force over a distance of 2m would be

F*s = 20500 * 2 = 40200 J

So c.40200 J is the correct answer

7 0
3 years ago
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