6x-8y=48
to find the x intercept set y=0
6x - 8*0 = 48
6x = 48
divide by 6 on each side
x =48/6
x=8
(8,0)
to find the y intercept set x=0
6(0) - 8y = 48
0 - 8y = 48
-8y = 48
divide by -8 on each side
y = -6
(0,-8)
Answer:
4/3
Step-by-step explanation:
If the ratio between the volumes of the first and the second cube is 64, the ratio between the sides is the cubic root of the ratio between the volumes, so:

![s1 / s2 = \sqrt[3]{64} = 4](https://tex.z-dn.net/?f=s1%20%2F%20s2%20%3D%20%5Csqrt%5B3%5D%7B64%7D%20%20%3D%204)
Doing the same for the second and third cubes, we have:

![s2/ s3 = \sqrt[3]{1/27} = 1/3](https://tex.z-dn.net/?f=s2%2F%20s3%20%3D%20%5Csqrt%5B3%5D%7B1%2F27%7D%20%20%3D%201%2F3)
So the ratio of the first cube side and the third cube side is:

Answer:
-13x+8
Step-by-step explanation:
add the x's including negatives
X + (2 + x) + (4 + x) = 60
3x + 6 = 60
3x = 54
x = 18
x + 2 = 20
x + 4 = 22
Their ages are 18, 20, 22