Question

Dinitrogen monoxide gas is collected at 19.0 °C in an evacuated flask with a measured volume of 30.0 L. When all the gas has been collected, the pressure in the flask is measured to be 0.500 atm . Calculate the mass and number of moles of dinitrogen monoxide gas that were collected. Be sure your answer has the correct number of significant digits.

Answer 1

Answer:

0.626 moles of dinitrogen monoxide gas was collected, this is 27.6 grams

Explanation:

Step 1: Data given

Temperature of Dinitrogen monoxide gas = 19.0 °C = 292 K

Volume of the flask = 30.0 L

Pressure in the flask = 0.500 atm

Step 2: Calculate moles of Dinitrogen monoxide gas

p*V = n*R*T

⇒with p = the pressure of the gas = 0.500 atm

⇒with V = the volume of the flask = 30.0 L

⇒with n = the number of moles of N2O gas = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 292 K

n = (p*V) / (R*T)

n = (0.500 * 30.0) / (0.08206 * 292)

n = 0.626 moles

Step 3: Calculate mass N2O gas

Mass N2O gas = moles N2O * molar mass N2O

Mass N2O = 0.626 moles * 44.013 g/mol

Mass N2O = 27.55 grams ≈ 27.6 grams

0.626 moles of dinitrogen monoxide gas was collected, this is 27.6 grams

Answer 2

Answer:

0.625 mol

27.5 g

Explanation:

Given data

• Gas: N₂O

• Molar mass (M): 44.01 g/mol

• Temperature (T): 19.0°C + 273.15 = 292.2 K

• Volume (V): 30.0 L

• Pressure (P): 0.500 atm

We can find the moles of dinitrogen monoxide gas using the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 0.500 atm × 30.0 L/0.0821 atm.L/mol.K × 292.2 K

n = 0.625 mol

Then, we can find the mass corresponding to 0.625 moles.

0.625 mol × 44.01 g/mol = 27.5 g