Each period corresponds to a principal energy level.
For balancing acidic solutions, we would need to add H+ ions to the correct side of the equation to balance the total number of atoms and the overall charge.
<span>Then amount of energy required to break the attractions among the solute particles and among the solvent particles is </span>less than the energy released as attractions form between solute and solvent particles.
Answer:
660kcal
Explanation:
The question is missing the concentration of the glucose solution. Standard glucose concentration for IV solution is 5% or 5g of glucose every 100mL of solution.
We need to determine how many grams of glucose are there inside the solution. The number of glucose in 3.3L solution will be:
3.3L * (1000mL / L) * (5g/100mL)= 165 g.
If glucose will give 4kcal/ g, then the total calories 165g glucose give will be: 165g * 4kcal/ g= 660kcal.
Four significant figures would be B. Because 0's before the decimal are not important, but 0's after the decimal are.
