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scoundrel [369]
3 years ago
9

What mass of hbr (in g) would you need to dissolve a 3.4 −g pure iron bar on a padlock?

Chemistry
1 answer:
vivado [14]3 years ago
5 0

<u>Given:</u>

Mass of pure iron (Fe) = 3.4 g

<u>To determine:</u>

Mass of HBr needed to dissolve the above iron

<u>Explanation:</u>

Reaction between HBr and Fe is

Fe + 2HBr → FeBr₂ + H₂

Based on the reaction stoichiometry-

1 mole of Fe reacts with 2 moles of HBr

# moles of Fe = mass of Fe/atomic mass of Fe = 3.4/56 g.mol⁻¹ = 0.0607 moles

Therefore # moles of HBr = 2*0.0607 = 0.1214 moles

Molar mass of HBr = 81 g/mole

Mass of HBr = 0.1214 moles * 81 g/mole = 9.83 g

Ans: Mass of HBR required is 9.83 g

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Answer:

The scaling factor is 5.

Explanation:

Hello there!

In this case, since the scaling factor is defined as the ratio of the molar mass of the molecular formula (complete) to the empirical formula (simplified), it is possible to compute it for the empirical formula of CH2O whose molar mass is 30 g/mol (12+2+16) as shown below:

sf=150/30=5

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6 0
3 years ago
Elements that have the following qualities: Lustrous, Solid at Room Temperatures, They react and form Basic Compounds, Great con
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Answer:

They are classified as METALS.

Explanation:

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8 0
3 years ago
Calculate the entropy change for the reaction: Fe2O3(s) +3C(s) -&gt; 2Fe(s) + 3CO(g)Entropy data:Fe2O3(s): 90 J/K molC(s): 5.7 J
Annette [7]

Explanation:

We are given: entropy of Fe2O3 = 90J/K.mol

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\begin{gathered} \Delta S\text{ = S}_{products}-S_{reactants} \\  \\ \text{       = \lparen3}\times198+2\times27.2)-(3\times5.7+90) \\  \\ \text{       = 541.3J/K.mol} \end{gathered}

Answer:

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5 0
1 year ago
Explain why rain water is not pure
Leviafan [203]

Answer:

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Explanation:

5 0
3 years ago
Read 2 more answers
63 C = _____ 63 K 336 K 210 K 163 K
swat32
T K = ºC + 273

T = 63 + 273

T = 336 K

hope this helps!

4 0
3 years ago
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