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astraxan [27]
3 years ago
6

The polarity of the water molecule aids in dissolving compounds. This is demonstrated by all but which statement?A)The water mol

ecules group together in clumps.B)The partial negative oxygen atom end of the water molecule surround cations.C)The partial positive hydrogen atom end of the water molecule surround anions.D)The water molecules also dissolve nonelectrolytes by creating a hydration sphere around the molecule.
Chemistry
2 answers:
nikdorinn [45]3 years ago
6 0

Answer:

A

Explanation: this statement does not demonstrate how water molecules help dissolve compounds.

never [62]3 years ago
3 0

Answer:

The correct option is;

A) The water molecules group together in clumps.

Explanation:

To answer the question, we look at each option as follows

A)  The water molecules group together in clumps

This does not aid dissolution of compounds as clumping excludes non polar molecules, making them less soluble.

B) The partial negative oxygen atom end of the water molecule surround cations.

When an ionic compound such as NaCl is dissolved in water, the oxygen atoms surround the positive Na⁺ cations in the solution.

C) The partial positive hydrogen atom end of the water molecule surround anions

When the ionic NaCl compound  is dissolved in water, the hydrogen atoms surround the negative Cl⁻ anions  in the solution.

D) The water molecules also dissolve nonelectrolytes by creating a hydration sphere around the molecule.

Water is able to dissolve nonelectrolytes  by creating an hydration sphere or hydration shell around the molecule.

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Some fertilizer blends contain magnesium nitrate (MgNO3). Suppose that a chemist has 1.24 liters of a 2.13 M solution of magnesi
tamaranim1 [39]

Initial concentration of magnesium nitrate M1 = 2.13 M

Initial volume of magnesium nitrate, MgNO3  V1 = 1.24 L

Final concentration of MgNO3, M2 = 1.60 M

Let the final volume of MgNO3 upon dilution be V2

Formula to use:

M1*V1 = M2*V2

V2 = M1*V1/M2

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Thus, the final volume of magnesium nitrate solution upon dilution is 1.65 L

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Warm and cold air come together and neither air mass moves what kind of front is that
Marrrta [24]

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3 0
3 years ago
g Suppose 0.0350 g M g is reacted with 10.00 mL of 6 M H C l to produce aqueous magnesium chloride and hydrogen gas. M g ( s ) +
iren2701 [21]

Answer:

Mg will be the limiting reagent.

Explanation:

The balanced reaction is:

Mg + 2 HCl → MgCl₂ + H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Mg: 1 mole
  • HCl: 2 moles
  • MgCl₂: 1 mole
  • H₂: 1 mole

Being the molar mass of each compound:

  • Mg: 24.3 g/mole
  • HCl: 36.45 g/mole
  • MgCl₂: 95.2 g/mole
  • H₂: 2 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Mg: 1 mole* 24.3 g/mole= 24.3 g
  • HCl: 2 moles* 36.45 g/mole= 72.9 g
  • MgCl₂: 1 mole* 95.2 g/mole= 95.2 g
  • H₂: 1 mole* 2 g/mole= 2 g

0.0350 g of Mg is reacted with 10.00 mL (equal to 0.01 L) of 6 M HCl.

Molarity being the number of moles of solute that are dissolved in a certain volume, expressed as:

Molarity=\frac{number of moles of solute}{volume}

in units \frac{moles}{liter}

then, the number of moles of HCl that react is:

6 M=\frac{number of moles of HCl}{0.01 L}

number of moles of HCl= 6 M*0.01 L

number of moles of HCl= 0.06 moles

Then you can apply the following rule of three: if by stoichiometry 2 moles of HCl react with 24.3 grams of Mg, 0.06 moles of HCl react with how much mass of Mg?

mass of Mg=\frac{0.06 moles of HCl* 24.3 grams of Mg}{2 moles of HCl}

mass of Mg= 0.729 grams

But 0.729 grams of Mg are not available, 0.0350 grams are available. Since you have less mass than you need to react with 0.06 moles of HCl, <u><em>Mg will be the limiting reagent.</em></u>

7 0
3 years ago
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