The correct answer to this question is this one:
Assuming all the barium bromide dissolved (which it should), the concentration of BaBr2 in solution should be zero: it should all dissociate into Ba+2 and 2Br- ions.
Turn those grams of BaBr2 into moles of BaBr2, then divide by the volume to get the concentration.
Recognize that every formula unit of BaBr2 has one ion of Ba+2, and 2 ions of Br-1. That means that when this substance dissociates, you'll get one concentration of Ba+2 ions, and a concentration of Br- ions TWICE as large. Whatever the concentration of Ba+2 ions is that you calculate, double it for the conentration of the Br-1 ion.
Option A) Decreased temperature keeps gases like carbon dioxide dissolved.
Carbonation is made with CO2 which is also know as liquid carbonic. The low temperature favors higher solubility of CO2 in water
Answer:
The answer to your question is: Molarity = 0.078
Explanation:
Data
HCl
V = 250 ml
T = 27°C = 300 °K
P = 141 mmHg = 0.185 atm
V2 = 70 ml
NaOH
V = 24.3 ml
Molarity NaOH = ?
Process
1.- Calculate the number of moles of HCl
PV = nRT
n = PV / RT
R = 0.082 atm l / mol K
n = (0.185)(0.25) / (0.082)(300)
n = 0.046 / 24.6
n = 0.0019 moles
2.- Calculate molarity of HCl
Molarity = moles / volume
Molarity = 0.0019 / 0.070
Molarity = 0.027
3.- Write the balanced equation
HCl + NaOH ⇒ H₂O + NaCl
Here, we observe that the proportion HCl to NaOH is 1:1 .
Then 0.0019 moles of HCl reacts with 0.0019 moles of NaOH.
4.- Calculate the molarity of NaOH.
Molarity = 0.0019 / 0.0243
Molarity = 0.078