Hi!
The percent composition by mass of nitrogen in NH₄OH is
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4/35×100.
To calculate percent composition by mass of an atom in a chemical compound, you'll need to divide the atomic mass of the element (AM), which is
14 for Nitrogen, by the molar mass of the entire compound (MM) and multiply the result by 100. The formula for calculating percent composition is the following:
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Have a nice day!</span>
It would be considered NEUTRAL
Answer:
A
B
C
Explanation:
A B and C are heterogeneous because they don’t have all the same components throughout. D is homogeneous because kool aid dissolves into the water.
The specific heat capacity of the metal given the data from the question is 0.66 J/gºC
<h3>Data obtained from the question</h3>
- Mass of metal (M) = 76 g
- Temperature of metal (T) = 96 °C
- Mass of water (Mᵥᵥ) = 120 g
- Temperature of water (Tᵥᵥ) = 24.5 °C
- Equilibrium temperature (Tₑ) = 31 °C
- Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC
- Specific heat capacity of metal (C) =?
<h3>How to determine the specific heat capacity of the metal</h3>
The specific heat capacity of the sample of the metal can be obtained as follow:
Heat loss = Heat gain
MC(M –Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)
76 × C × (96 – 31) = 120 × 4.184 × (31 – 24.5)
C × 4940 = 3263.52
Divide both side by 4940
C = 3263.52 / 4940
C = 0.66 J/gºC
Learn more about heat transfer:
brainly.com/question/6363778
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Answer:
This question lacks options, the options are:
A. 2.89 x 1022
B. 8.66 x 1022
C. 3.66 x 1023
D. 1.10 x 1024
E. 3.29 x 1024
The answer is C. 3.66 × 10^23
Explanation:
In the chemical compound given as follows: Co2(HPO4)3, hydrogenphosphate ion is (HPO4)3.
Number of moles of hydrogenphosphate ion can be calculated using the formula
mole (n) = mass (m) /molar mass (MM)
Molar mass of (HPO4)3;
{1 + 31 + 16(4)}3
= {32 + 64)3
= (96)3
= 288g/mol
mole = 175/288
mole = 0.6076
mole = 0.607mol
The formula of units of hydrogenphosphate ion can be calculated by multiplying number of moles by Avogadro's number (6.022 × 10²³)
6.022 × 10²³ × 0.607
= 3.655 × 10²³
= 3.66 × 10²³