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ikadub [295]
3 years ago
15

How many grams of magnesium chloride are needed to make 700ml of a 1.4 m solution?

Chemistry
1 answer:
eduard3 years ago
4 0
Molarity is defined as the number of moles of solute in 1 L solution
molarity of MgCl₂ solution to be prepared - 1.4 M
volume of the solution to be prepared - 700 mL
the number of moles of MgCl₂ in 1 L - 1.4 M
therefore 700 mL should contain - 1.4 mol/L x 0.700 L = 0.98 mol 
molar mass of MgCl₂ - 95.2 g/mol 
mass of MgCl₂ required - 0.98 mol x 95.2 g/mol = 93.3 g
mass of MgCl₂ required is 93.3 g
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Determine the change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizi
uysha [10]

Answer: The change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizing compound is dissolved in it is 2.9^0C

Explanation:

Elevation in boiling point:

T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_b = boiling point of solution = ?

T^o_b = boiling point of pure carbon disulfide= 46.2^oC

k_b = boiling point constant  =2.34^0Ckg/mol

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute = 35.0 g

w_1 = mass of solvent (carbon disulphide) = 397.7 g

M_2 = molar mass of solute = 70.0 g/mol

Now put all the given values in the above formula, we get:

(T_b-46.2)^oC=1\times (2.34^oC/m)\times \frac{(35.0g)\times 1000}{70.0\times (397.7g)}

T_b=49.1^0C

Therefore, the change in boiling point is (49.1-46.2)^oC=2.9^0C

5 0
3 years ago
can someone please help me ill give brainest? Will the velocity of the book change as it moves across the surface WITH friction?
Lady bird [3.3K]

Answer:

Yes, it will.

Explanation:

The friction of the surface will tug at the book and lower it's velocity, causing it to slow down.

7 0
3 years ago
Read 2 more answers
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vampirchik [111]

Answer:

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2 years ago
A gas has a pressure of 450 mmHg at 100 degrees Celsius. What will its new pressure be when the temperature rises 200 degrees Ce
Ahat [919]

Answer:

P2 = 900 mmHg.

Explanation:

Given the following data;

Initial pressure = 450 mmHg

Initial temperature = 100°C

Final temperature = 200°C

To find the final pressure, we would use Gay Lussac's law;

Gay Lussac states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

PT = K

\frac{P1}{T1} = \frac{P2}{T2}

Making P2 as the subject formula, we have;

P_{2}= \frac{P1}{T1} * T_{2}

P_{2}= \frac{450}{100} * 200

P_{2}= 4.5 * 200

Final pressure, P2 = 900 mmHg.

3 0
3 years ago
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Explanation: MY own word's.

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3 years ago
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