I believe this would be the solution. Remember to first convert mass of KClO3 to moles and then use the mole to mole ratio to find the moles of KCl produced, and then convert this value into grams. To solve for the mass of KCl produced.
Molar ratio is the quantity which will correctly convert between two different substances.
Answer: Option B
<u>Explanation:
</u>
Molar ratio is used to determine the number of moles of reactants required to convert to desired number of moles of the products and vice versa. As moles are the coefficient written in any chemical equation. The ratio of the number of moles of the reactants to the number of moles of the products will help to determine the molar ratio.
This molar ratio is used as the conversion factor to determine number of moles required in the reactant side for the reactants to form a desired product of desired moles. We can also determine the number of moles utilized from the reactants from the moles obtained in the products using this molar ratio conversion factor.
Answer:
The new pressure is 1.70L
Explanation:
Because its going down by 0.5
The constant use of water flow throwout nature and the way that we use it now isint good and most likly we will be out of water by the year 2055
Answer:
49.5J/°C
Explanation:
The hot water lost some energy that is gained for cold water and the calorimeter.
The equation is:
Q(Hot water) = Q(Cold water) + Q(Calorimeter)
<em>Where:</em>
Q(Hot water) = S*m*ΔT = 4.184J/g°C*54.56g*(80.4°C-59.4°C) = 4794J
Q(Cold water) = S*m*ΔT = 4.184J/g°C*47.24g*(59.4°C-40°C) = 3834J
That means the heat gained by the calorimeter is
Q(Calorimeter) = 4794J - 3834J = 960J
The calorimeter constant is the heat gained per °C. The change in temperature of the calorimeter is:
59.4°C-40°C = 19.4°C
And calorimeter constant is:
960J/19.4°C =
<h3>49.5J/°C</h3>
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