High pressure systems entail sinking air, while lows entail rising air. High pressure systems form where air converges in the higher levels of the atmosphere. The converging air has nowhere to go and is forced to sink toward the ground. This sinking effect inhibits cloud formation and therefore precipitation.
Answer:
Review each answer in the explanation part
Explanation:
Identify a problem or need = Aerospace engineers need a lightweight material to build a jet
Note: Identify a problem is related always with a need.
After identify the problem the next stage is the design
Design a solution = Engineers determine what features the material must have.
Note: The design process implies the choice of the materials and the proper numeric calculations.
Implement the solution = Engineers test a carbon - plastic compound in a wind tunnel.
Note: after the design, the following process is the built of the equipment and the different tests.
Evaluate the solution = The carbon-plastic compound is redesigned to save maximun energy.
Note: After testing, you enter a part of re-design that means making improvements to the already constructed.
Answer:
The total surface are of the bowl is given by: 0.0532*pi m² (approximately 0.166533 m²)
Explanation:
The total surface area of the semi-spherical bowl can be decomposed in three different sections: 1) an outer semi-sphere of radius 12 cm, 2) an inner semi-sphere of radius 10 cm, and 3) the edge, which is a 2-dimensional ring with internal radius of 10 cm and external radius of 12 cm. We will compute the areas independently and then sum them all.
a) Outer semi-sphere:
A1 = 2*pi*r² = 2*pi*(12 cm)² = 288*pi cm² = 904.78 cm²
b) Inner semi-sphere:
A2 = 2*pi*(10 cm)² = 200*pi cm² = 628.32 cm²
c) Edge (Ring):
A3 = pi*(r1² - r2²) = pi*((12 cm)²-(10 cm)²) = pi*(144-100) cm² = 44*pi cm² = 138.23 cm²
Therefore, the total surface area of the bowl is given by:
A = A1 + A2 + A3 = 288*pi cm² + 200*pi cm² + 44*pi cm² = 532*pi cm² (approximately 1665.33 cm²)
Changing units to m², as required in the problem, we get:
A = 532*pi cm² * (1 m² / 10, 000 cm²) = 0.0532*pi m² (approximately 0.166533 m²)
i think so it is frequency
B) Copper atoms have a loosely held free electron in their outer shell that is able to move freely to other atoms.
