Question

You need to construct a 100 pF capacitor for a science project. You plan to cut two L x L metal squares and insert small spacers between their corners. The thinnest spacers you have are 0.20 mm thick. What is the proper value of L?

Answer 1

Answer:

value of L = 4.75 cm

Explanation:

given data

capacitor =  100 pF = 100 × $10^{-12}$ F

thick = 0.20 mm = 2 × $10^{-4}$  m

solution

we get here area of each plate that is

area = L²   .......................1

and

Capacitance, C = εo A ÷ d    ..................2

put here value so we get

100 × $10^{-12}$ = 8.854 × $10^{-12}$   × L² ÷  ( 2 × $10^{-4}$ )

solve it and we will get

L =  0.047528 m

value of L = 4.75 cm