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Cloud [144]
3 years ago
13

In a police ballistics test, a 10.0-g bullet moving at 300 m/s is fired into a 1.00-kg block at rest. The bullet goes through th

e block almost instantaneously and emerges with 50.0% of its original speed. What is the speed of the block just after the bullet emerges
Physics
1 answer:
natta225 [31]3 years ago
3 0

Answer:

Speed of block after the bullet emerges = 1.5 m/s

Explanation:

Here momentum is conserved.

Initial momentum = Final momentum.

Mass of bullet = 10 g = 0.01 kg

Initial Velocity of bullet = 300 m/s

Mass of block = 1 kg

Initial Velocity of block = 0 m/s

Final Velocity of bullet = 50% of initial velocity. = 150 m/s

We need to find final velocity of block. Let it be v

We have

Initial momentum = 0.01 x 300 + 1 x 0 = 3 kg m/s

Final momentum = 0.01 x 150 + 1 x v = 1.5 + v

Equating

3 = 1.5 + v

v = 1.5 m/s

Speed of block after the bullet emerges = 1.5 m/s

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Answer:

The maximum height that the rocket reaches is 645.5 m.

Explanation:

Given that,

Mass = 10000 kg

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Distance = 525 m

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v=\sqrt{2\times2.25\times525}

v=48.60\ m/s

We need to calculate the maximum height with initial velocity

Using equation of motion

v^2=u^2-2gh

h=\dfrac{v^2-u^2}{-2g}

Put the value in the equation

h=\dfrac{0-(48.60)^2}{-2\times9.8}

h=120.50\ m

The total height  reached by the rocket is

h'=s+h

h'=525+120.50

h'=645.5\ m

Hence, The maximum height that the rocket reaches is 645.5 m.

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Answer:

32 °C.

Explanation:

Hola.

En este caso, debemos entender que la relación entre el calor y la temperatura viene dada por:

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\Delta T_{nuevo}=2*16\°C\\\\\Delta T_{nuevo}=32\°C

¡Saludos!

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