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Cloud [144]
3 years ago
13

In a police ballistics test, a 10.0-g bullet moving at 300 m/s is fired into a 1.00-kg block at rest. The bullet goes through th

e block almost instantaneously and emerges with 50.0% of its original speed. What is the speed of the block just after the bullet emerges
Physics
1 answer:
natta225 [31]3 years ago
3 0

Answer:

Speed of block after the bullet emerges = 1.5 m/s

Explanation:

Here momentum is conserved.

Initial momentum = Final momentum.

Mass of bullet = 10 g = 0.01 kg

Initial Velocity of bullet = 300 m/s

Mass of block = 1 kg

Initial Velocity of block = 0 m/s

Final Velocity of bullet = 50% of initial velocity. = 150 m/s

We need to find final velocity of block. Let it be v

We have

Initial momentum = 0.01 x 300 + 1 x 0 = 3 kg m/s

Final momentum = 0.01 x 150 + 1 x v = 1.5 + v

Equating

3 = 1.5 + v

v = 1.5 m/s

Speed of block after the bullet emerges = 1.5 m/s

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The time for half the atoms in a radioactive substance to disintegrate

https://www.vocabulary.com/dictionary/half-life
6 0
3 years ago
If the second harmonic of a certain string is 42 Hz, what is the fundamental frequency of the string?
stich3 [128]
I would think that you would have to do 42/2=21Hz, but I'm not sure...
5 0
3 years ago
The potential energy stored in the compressed spring of a dart gun, with a spring constant of 32.50 N/m, is 0.640 J. Find by how
liraira [26]

Answer:

A

   x = 0.198456 \ m

B

    h  =  1.3061 \  m

C

 v =  5.06 \  m/s

D

  d = 4.0273 \  m

Explanation:

Considering the first question

From the question we are told that

   The spring constant is  k  =  32.50 N/m

    The potential energy is  PE  =  0.640 \ J

Generally the potential  energy stored in spring  is mathematically represented as   PE  =  \frac{1}{2}  *  k  *  x^2

=>    0.640=  \frac{1}{2}  * 32.50  *  x^2  

=>    x = \sqrt{0.03938}  

=>    x = 0.198456 \ m  

Considering the second question

 From the question we are told that

   The mass of the dart is  m =  0.050 kg

Generally from the law of energy conservation

         PE =  mgh

=>       0.640   =  0.050 *  9.8  *  h

=>      h  =  1.3061 \  m

Considering the third  question

   The height at which the dart was fired horizontally is  H  =   3.90\  m

Generally  from the law of energy conservation

         PE = KE

Here  KE is kinetic energy of the dart which is mathematical represented as

     KE  =  \frac{1}{2}  *  mv^2

=>      0.640 =  \frac{1}{2}  * 0.050 *  v^2

=>       v^2 = 25.6

=>       v =  5.06 \  m/s

Considering the fourth question

Generally the total time of flight of the dart is mathematically represented as

       t  =  \frac{ 2 *  H }{g}

=>     t  =  \frac{ 2 * 3.90 }{9.8 }

=>     t  =  0.7959 \ s

Generally the  horizontal distance from the equilibrium position to the ground is  mathematically represented as

       d =  v  *   t

=>     d = 5.06  *   0.7959

=>     d = 4.0273 \  m

5 0
3 years ago
3.
ratelena [41]

Answer:

1.84 kJ  (kilojoules)

Explanation:

A specific heat of 0.46 J/g Cº means that it takes 0.46 Joules of energy to raise the temperature of 1 gram of iron by 1 Cº.

If we want to heat 50 g of iron from 20° C to 100° C, we can make the following calculation:

Heat = (specific heat)*(mass)*(temp change)

Heat = (0.46 J/g Cº)*(50g)*(100° C -  20° C)

[Note how the units cancel to yield just Joules]

Heat = 1840 Joules, or 1.84 kJ

[Note that the number is positive:  Energy is added to the system.  If we used cold iron to cool 50g of 100° C water, the temperature change would be (Final - Initial) or (20° C - 100° C).  The number is -1.84 kJ:  the negative means heat was removed from the system (the iron).

8 0
2 years ago
In order for work to take place the energy present must be related to the movement of the object.
kaheart [24]

This is another one of those muddy misleading questions, followed by
a muddy group of choices from which an answer must be selected.

a).  is absurd.  There's no such thing as a "balanced force", only
a balanced group of forces.

b).  is probably the choice the question is aiming for.

c).  is not so.  The engines of an airplane do plenty of work lifting the plane
off the ground, although the force of the engines is never directed upward.

d).  is really awkward.  The object's motion is almost never the cause of the force.
The force is almost always the cause of the object's motion.

Now for the big 800-lb gorilla in the room:  No moving object needs to be involved
in order for energy to be flowing or work to be getting done.

-- A radio wave radiates through space.  Straighten out a wire coat-hanger and
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through the wire, and you can drain the electrical energy out the bottom of it.  

-- A light bulb is shining.  Some distance away, something it's shining on
gets warm, because of the heat energy that has shot across to it from the
light bulb and soaked into it.

-- A lightning bolt jumps from the ground to a passing cloud.  Or, if you feel
more comfortable with it, a lightning bolt jumps from a cloud to the ground.
It doesn't matter.  Either way, there's enough energy splashing around to
ignite houses, zap TVs and computers, melt concrete, vaporize water, and
light up a city.  Although nothing is moving.

5 0
3 years ago
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