Question

The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telescope is 9.21 × 104 N, and the mass of Earth is 5.98 × 1024 kg, what is the mass of the telescope? Round the answer to the nearest whole number.

Answer 1

The Answer is 11,121 Kg

Answer 2

Answer:0.01Kg

Explanation:

F = GM1M2 / r²

F= Gravitational force

G= Gravitaional force constant

M1 = Mass of Earth

M2 = Mass of telescope

r = distance apart between the two bodies

F = G*M1*M2 / r²

Make M2 the subject of formula

M2 = Fr²/Gm1

M2 = (9.21*10^4) * (6940)² / (6.674*10^-11) * 5.98*10^24

M2 = 4.435*10^12 / 3.991*10^14

M2 = 0.0111kg ~0.1kg