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andre [41]
3 years ago
5

The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telesc

ope is 9.21 × 104 N, and the mass of Earth is 5.98 × 1024 kg, what is the mass of the telescope? Round the answer to the nearest whole number.
Physics
2 answers:
kumpel [21]3 years ago
6 0
The Answer is 11,121 Kg
dezoksy [38]3 years ago
3 0

Answer:0.01Kg

Explanation:

F = GM1M2 / r²

F= Gravitational force

G= Gravitaional force constant

M1 = Mass of Earth

M2 = Mass of telescope

r = distance apart between the two bodies

F = G*M1*M2 / r²

Make M2 the subject of formula

M2 = Fr²/Gm1

M2 = (9.21*10^4) * (6940)² / (6.674*10^-11) * 5.98*10^24

M2 = 4.435*10^12 / 3.991*10^14

M2 = 0.0111kg ~0.1kg

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10. How much total work do you do when you lift a 50 kg microwave 1.0 m off the ground and then push it 1.0 m
Mariulka [41]

Work formula:

W = Fd\cos(\theta)

F = 50N, d = 1.0 m

When you lift something straight up, the angle of the force is 90º

cos(90º) is 0, so there's no work done when you lift the microwave off the ground

W = (50N)(1.0)(0) = 0

F = 50N, d = 1.0 m

When you push the microwave, the angle is 0º and cos(0º) is 1. So there is work done here:

W = (50 N)(1.0m)(1)

W = 50

total work = 50 joules

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3 years ago
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drek231 [11]

Answer:

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3 years ago
Un atleta de 70 kg de masa que ha efectuado un salto de altura cae una vez que ha
Allushta [10]

Answer:

a) the elastic force of the pole directed upwards and the force of gravity with dissects downwards

Explanation:

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therefore the forces are the elastic force of the pole directed upwards and the force of gravity with dissects downwards

b) when it falls, in this case the only force to act is batrachium by the planet, this is a projectile movement for very high angles

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Name the Organs and functions of digestive system
Alexxx [7]
You forgot to add a photo.
6 0
3 years ago
A car’s tire rotates 5.25 times in 3 seconds. What is the tangential velocity of the tire?
Lena [83]

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.

<h3>Angular velocity of the tire</h3>

The angular velocity of the tire is the rate of change of angular displacement of the tire with time.

The magnitude of the angular velocity of the tire is calculated as follows;

ω = 2πN

where;

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ω = 2π x (5.25 / 3)

ω =  11 rad/s

<h3>Tangential velocity of the tire</h3>

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.

The magnitude of the tangential velocity is caculated as follows;

v = ωr

where;

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v = 11r m/s

Learn more about tangential velocity here: brainly.com/question/25780931

4 0
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