The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telesc
2 answers:
You might be interested in
Answer:
The density is
Explanation:
From the question we are told that
The weight in air is
The weight in water is
The weight in a unknown liquid is
Now according to Archimedes principle the weight of the object in water is mathematically represented as
Where is he mass of the water displaced
substituting value
Now according to Archimedes principle the weight of the object in unknown is mathematically represented as
Where is he mass of the unknown liquid displaced
substituting value
dividing equation 2 by equation 1
=>
Now since the volume of water and liquid displaced are the same then
This because
So if volume is constant
mass = constant * density
Where is the density of the liquid
and is the density of water which is a constant with a value
So
Answer: 0.5 seconds or 2.625 seconds
Explanation:
At t = 0, The ball is 4 ft above the ground.
The height of the football varies with time in the following way:
s(t) = -16 t² + 50 t + 4
we need to find the time in which the height would of the football would be 25 ft:
⇒25 = -16 t² + 50 t + 4
we need to solve the quadratic equation:
⇒ 16 t² - 50 t + 21 = 0
⇒ t = 0.5 s or 2.625 s
Therefore, at t = 0.5 s or 2.625 s, the football would be 25 ft above the ground.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
The High Voltage Rating for Auto - Transformer is 86kV
The Low Voltage Rating for Auto - Transformer is 78kV
The MVA rating is 268.75
b
The efficiency is 99.4%
Explanation:
From the question we are given are given that
The transformer has Mega Volt Amp rating of 25MVA
The frequency is 60-Hz
Voltage rating 8.0kV : 78kV
The short circuit test gives : 453kV,321A,77.5kW
The open circuit test gives : 8.0kV, 39.6A, 86.2kW
This can be represented on a diagram shown on the second uploaded image
From this diagram we can deduce that the The High Voltage Rating for Auto - Transformer is 86kV and the Low Voltage Rating for Auto - Transformer is 78kV
Now to obtain the current flowing through the 8kV coil in the Auto-transformer we have
The volt will cancel each other
Now to obtain the required MVA rating we would multiply the value of Power obtained during the open circuit test by the value of the current calculated.we are making use of the power obtain during open circuit testing because the transformer at this point is not under any load.
We need to understand that Iron losses is due to open circuit test which has power = 86.2kW
While copper loss is due to short circuit test which has power = 77.5kW
The the current flowing through the secondary coil as shown in the circuit diagram can be obtained as
Now the efficiency can be obtained as thus
=99.941%
