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ale4655 [162]
3 years ago
5

How to solve 8x^3-27=0

Mathematics
2 answers:
love history [14]3 years ago
4 0
8x³-27=0
8x³=27
x³=27/8
x=∛27/∛8
x=3/2
densk [106]3 years ago
3 0
Factor using difference of cubes, and set each factor equal to 0.
x=(-3+3i\sqrt(3))/(4),(-3-3i\sqrt(3))/(4),(3)/(2)
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Papessa [141]
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cross multiply
(4)(x) = (3)(340)
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or this way.....

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4 years ago
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3 years ago
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3 0
3 years ago
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7 0
3 years ago
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sineoko [7]
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3 0
3 years ago
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