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3 years ago

What solutes do not dissolve well in water?

Physics

2 answers:

hammer [34]3 years ago

6 0

Answer:

Many substances do not dissolve in water and that is because they are non-polar and do not interact well with water molecules. A common example is oil and water. Oil contains molecules that are non-polar, thus they do not dissolve in water.

Explanation:

blagie [28]3 years ago

5 0

Answer:

Many solutes do not dissolve in water because they are non-polar. Non-polar molecules do not interact well with water molecules.

A perfect example I found is oil and water. oil does not dissolve in water.

Explanation:

If you have any questions feel free to ask in the comments - Mark

Also when you have the chance please mark me brainliest.

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How much of earths gravitational force acts on everyone and everything onboard of the international space station?

liraira [26]

B) Approx. 90%

The actual value is 0.89g

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3 years ago

Two pure tones are sounded together. The drawing shows the pressure variations of the two sound waves, measured with respect to

amm1812

Answer:

4.13Hz

Explanation:

f1 = 1/t1 = 1/0.022 = 45.45 Hz

f2 = 1/t2 = 1/0.0242= 41.32 Hz

No. of beats

= 45.45- 41.32

~ 4.13Hz

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2 years ago

What do we measure sound intensity in?

stira [4]

Answer:

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2 years ago

Read 2 more answers

An instrument is thrown upward with a speed of 15 m/s on the surface of planet X where the acceleration due to gravity is 2.5 m/

Katen [24]

<h2>Answer: 12 s</h2>

Explanation:

The situation described here is parabolic movement. However, as we are told the instrument is thrown upward from the surface, we will only use the equations related to the Y axis.

In this sense, the main movement equation in the Y axis is:

$y-y_{o}=V_{o}.t-\frac{1}{2}g.t^{2}$ (1)

Where:

$y$ is the instrument's final position

$y_{o}=0$ is the instrument's initial position

$V_{o}=15m/s$ is the instrument's initial velocity

$t$ is the time the parabolic movement lasts

$g=2.5\frac{m}{s^{2}}$ is the acceleration due to gravity at the surface of planet X.

As we know $y_{o}=0$ and $y=0$ when the object hits the ground, equation (1) is rewritten as:

$0=V_{o}.t-\frac{1}{2}g.t^{2}$ (2)

Finding $t$ :

$0=t(V_{o}-\frac{1}{2}g.t^{2})$ (3)

$t=\frac{2V_{o}}{g}$ (4)

$t=\frac{2(15m/s)}{2.5\frac{m}{s^{2}}}$ (5)

Finally:

$t=12s$

3 0

3 years ago

Why is it not posible to see the other waves on the electromagnetic spectrum???

Montano1993 [528]

It is not possible to see the other waves on the electromagnetic spectrum because only other species can see the other parts of the spectrum because they have different components in their eyes than we do, therefore, only allowing us to see a
portion of the spectrum, which is visible light.

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3 years ago