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Evgen [1.6K]
3 years ago
7

For metals like aluminum and iron, which are found naturally in nature as oxides, the refining process requires that the metals

be __________________ by gaining electrons to yield the final metallic product (1 point).
Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
3 0

Answer:

reduced

Explanation:

To win the metallic product from the oxide, it demands that the metal be reduced.

During reduction a metal will:

  • gain electrons.
  • there would be removal of oxygen from the specie
  • there would be decrease in oxidation number of the atom
  • decrease in the number of electronegative atom surrounding the element.

The specie that is reduced will become the oxidant and reducing agent in the chemical reaction.

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What amount of energy is required to change a spherical drop of water with a diameter of 1.80 mm to three smaller spherical drop
Gekata [30.6K]
This is a straightforward question related to the surface energy of the droplet. 

<span>You know the surface area of a sphere is 4π r² and its volume is (4/3) π r³. </span>

<span>With a diameter of 1.4 mm you have an original droplet with a radius of 0.7 mm so the surface area is roughly 6.16 mm² (0.00000616 m²) and the volume is roughly 1.438 mm³. </span>

<span>The total surface energy of the original droplet is 0.00000616 * 72 ~ 0.00044 mJ </span>

<span>The five smaller droplets need to have the same volume as the original. Therefore </span>

<span>5 V = 1.438 mm³ so the volume of one of the smaller spheres is 1.438/5 = 0.287 mm³. </span>

<span>Since this smaller volume still has the volume (4/3) π r³ then r = cube_root(0.287/(4/3) π) = cube_root(4.39) = 0.4 mm. </span>

<span>Each of the smaller droplets has a surface area of 4π r² = 2 mm² or 0.0000002 m². </span>

<span>The surface energy of the 5 smaller droplets is then 5 * 0.000002 * 72.0 = 0.00072 mJ </span>
<span>From this radius the surface energy of all smaller droplets is 0.00072 and the difference in energy is 0.00072- 0.00044 mJ = 0.00028 mJ. </span>

<span>Therefore you need roughly 0.00028 mJ or 0.28 µJ of energy to change a spherical droplet of water of diameter 1.4 mm into 5 identical smaller droplets. </span>
7 0
3 years ago
1. The diagram models the forces acting on a box. 2N 2N- Box - 2 N 5 N Which of the following best describes the motion of the b
zhenek [66]

Answer: The box is moving downward with increasing speed.

Explanation:

6 0
3 years ago
What is The substance that could not be dissolved and has settled out of a solution
lys-0071 [83]

homogeneous mixture not pure, but is spread out the same throughout

concentration, a measure of the amount of solute dissolved in a solvent

mixture,two or more substances that do not chemically combine, salt and pepper

solute,substance that is dissolved in the solution

5 0
3 years ago
How can ionic compounds be neutral?
Rudiy27
If u seperate them into halves at a time

8 0
3 years ago
A mixture of water and acetone at 756 mm boils at 70.0°C. The vapor pressure of acetone is
Tatiana [17]

Given :

A mixture of water and acetone at 756 mm boils at 70.0°C.

The vapor pressure of acetone is  1.54 atm at 70.0°C, while the vapor pressure of water is 0.312 atm at the same temperature.

To Find :

The percentage composition of the mixture.

Solution :

By Raoult's law :

P=x_{acetone}P^o_{acetone}+x_{water}P^o_{water}\\\\x_{acetone}1.58+x_{water}0.312=\dfrac{756}{760}=0.995\ atm\\\\1.58x_a+0.312x_w=0.995......( 1 )

Also , x_a+x_b=1      ......( 2 )

Solving equation 1 and 2 , we get :

x_a=0.54\ and \ x_w=0.46 .

Mass of acetone ,

m_a=x_a\times MM_a\\\\m_a=0.54\times 58\\\\m_a=31.32\ g

Mass of water ,

m_w=x_w\times MM_w\\\\m_w=0.46\times 18\\\\m_a=8.28\ g

\%water =\dfrac{8.28}{8.28+31.32}\times 100\\\\\%water =20.9\%\\\\\%acetone =79.1\%

Hence , this is the required solution.

6 0
3 years ago
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