Answer:
148.04 kJ/mol
Explanation:
Let's consider the following thermochemical equation.
NO(g) + 1/2 O₂(g) → NO₂(g) ΔH°rxn = -114.14 kJ/mol
We can find the standard enthalpy of formation (ΔH°f) of NO(g) using the following expression.
ΔH°rxn = 1 mol × ΔH°f(NO₂(g)) - 1 mol × ΔH°f(NO(g)) - 1/2 mol × ΔH°f(O₂(g))
ΔH°f(NO(g)) = 1 mol × ΔH°f(NO₂(g)) - ΔH°rxn - 1/2 mol × ΔH°f(O₂(g)) / 1 mol
ΔH°f(NO(g)) = 1 mol × 33.90 kJ/mol - (-114.14 kJ) - 1/2 mol × 0 kJ/mol / 1 mol
ΔH°f(NO(g)) = 148.04 kJ/mol
Answer:
0.375 grams are needed to make 25 mL solution.
Explanation:
Mass of 
cuprous nitrate required to make 1 l of solution = 15 g.
1 L = 1000 mL
Mass of cuprous nitrate required to make 1000 mL of solution = 15 g
Mass of cuprous nitrate required to make 1 mL of solution:
Mass of cuprous nitrate required to make 25 mL of solution:
0.375 grams are needed to make 25 mL solution.
Answer:
this answer is b no u can it very easy
Explanation:
because solid and liquid can compress easily
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