Answer:
6%
Explanation:
Hello, for this case, we assume that the volume of the solution is 1L, thus, the mass is given by using the density as follows:
Now, the mass of the ethanol:
Finally, the by mass percent is:
%
%m=6%
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A student weighed out a 2.055 g sample of a cobalt chloride hydrate, ConClmpH2O, where n, m, and p are integer values to be dete
1 answer:
The given mass of cobalt chloride hydrate = 2.055 g
A sample of cobalt chloride hydrate was heated to drive off waters of hydration and the anhydrate was weighed.
The mass of anhydrous cobalt chloride = 1.121 g anhydrate.
The mass of water lost during heating = 2.055 g - 1.121 g = 0.934 g
Converting mass of water of hydration present in the hydrate to moles using molar mass:
Mass of water = 0.934 g
Molar mass of water = 18.0 g/mol
Moles of water =
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Answer : The volume of carbon dioxide will be, 5.6122 L
Solution : Given,
Moles of LiOH = 0.5 moles
Molar mass of carbon dioxide = 44 g/mole
Density of carbon dioxide = 0.00196 g/ml
First we have to calculate the mass of carbon dioxide.
The balanced reaction will be,
From the reaction we conclude that
As, 2 moles of LiOH absorbs 44 grams of carbon dioxide
So, 0.5 moles of LiOH absorbs grams of carbon dioxide
Mass of carbon dioxide = 11 g
Density of carbon dioxide = 0.00196 g/ml
Now we have to calculate the volume of carbon dioxide.
Volume of carbon dioxide = 5612.24 ml = 5.6122 L (1 L = 1000 ml)
Therefore, the volume of carbon dioxide will be, 5.6122 L