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Naddika [18.5K]
3 years ago
11

A student weighed out a 2.055 g sample of a cobalt chloride hydrate, ConClmpH2O, where n, m, and p are integer values to be dete

rmined. The student heated the sample to drive off the waters of hydration, reweighed the anhydride sample and found 1.121 g anhydrate
Chemistry
1 answer:
topjm [15]3 years ago
8 0

The given mass of cobalt chloride hydrate = 2.055 g

A sample of cobalt chloride hydrate was heated to drive off waters of hydration and the anhydrate was weighed.

The mass of anhydrous cobalt chloride = 1.121 g anhydrate.

The mass of water lost during heating = 2.055 g - 1.121 g = 0.934 g

Converting mass of water of hydration present in the hydrate to moles using molar mass:

Mass of water = 0.934 g

Molar mass of water = 18.0 g/mol

Moles of water = 0.934 g * \frac{1 molH_{2}O }{18 g H_{2}O } =0.0519 mol H_{2}O

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Charra [1.4K]
1) mass composition

N: 30.45%
O: 69.55%
   -----------
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2) molar composition

Divide each element by its atomic mass

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O: 69.55 / 16.00 = 4.346875

4) Find the smallest molar proportion

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N: 2.175 / 2.175 = 1

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=> n = 0.01769 moles

8) Find molar mass

molar mass = mass in grams / number of moles = 1.63 g / 0.01769 mol = 92.14 g / mol

9) Find how many times the mass of the empirical formula is contained in the molar mass

92.14 / 46.00 = 2.00

10) Multiply the subscripts of the empirical formula by the number found in the previous step

=> N2O4

Answer: N2O4
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