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3 years ago

How a non-polar molecule can ve madre of polar bonds?

Chemistry

1 answer:

Alenkinab [10]3 years ago

6 0

Answer:

Explanation:

i cant understand the complete question, can you reword it and ill answer

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Test Name: GR8_Sci_U07_USA_FY20

kumpel [21]

The distance from the star to the Earth

Explanation:

The absolute brightness of a star is a measure of the intrinsec luminosity of the star, i.e. it does not depend on the distance of the star from the Earth.

In other word, the absolute brightness is a measure of the luminosity of a star if all stars were placed at the same distance from Earth.

On the other hand, the relative brightness of a star is a measure of its luminosity as observed on Earth, therefore it does depend on the distance of the star from the Earth: the farther the star is, the more its luminosity will decrease, and vice-versa.

The star's absolute brightness, therefore, depends only on the characteristics of the star itself, namely:

- The absolute magnitude of the star

- The rate at which the star produces energy via nuclear fusion

- The rate at which the star releases energy via electromagnetic radiation

Therefore, the only factor that does NOT change if the absolute brightness of a star changes is

- The distance from the star to the Earth

Learn more about planets and stars:

brainly.com/question/2887352

brainly.com/question/10934170

#LearnwithBrainly

8 0

3 years ago

HELP I’ll give Brainliest

Elena-2011 [213]

Answer: The first question’s answer is 2 and the second question answer is 3. 12.B, 13.C

Explanation:

6 0

3 years ago

What particles make up an atom?

Lisa [10]

Answer:

protons neutrons and electrons

8 0

2 years ago

When heated a sample consisting of only CaCO3 and MgCO3 yields a mixture of CaO and Mgo. If the weight of the combined oxides is

ExtremeBDS [4]

Answer:

38.83 % of CaCO3

61.17 % of MgCO3

Explanation:

where Moles of CaCO3 is equals to x and MgCO3 is y we have that...

CaCO3 molar mass = 100.09 g / mol = 100.09 x

MgCO3 molar mass = 84.31 g / mol = 84.31 y

decomposition reactions :

CaCO3 ---> CaO + CO2

MgCO3 ---> MgO + CO2

So we have that , Moles of CaO = Moles of CaCO3 = x

and Moles of MgO = Moles of MgCO3 = y

CaO molar mass = 56.08 g / mol

MgO molar mass = 40.30 g / mol

CaO = 56.08 x

MgO = 40.30 y

"If the weight of the combined oxides is equal to 51.00% of the initial sample weight,"

total mass of MgO and CaO = 51.00 % of Total Mass of MgCO3 and CaCO3

thus

56.08 x + 40.30 y = 0.51 ( 100.09 x + 84.31 y )

56.08 x + 40.30 y = 51.04 x + 42.99y

5.04 x = 2.7 y

y = 1.87 x

CaCO3 % in the sample

= 100.09 x × 100 / ( 100.09 x + 84.31 y )

= 10009 x / ( 100.09 x + 84.31 × 1.87 x )

= 10009 x / ( x ( 100.09 + 157.66 ) )

= 10009 / 257.75

= 38.83 %

MgCO3 % in the sample

= 100 - 38.83

= 61.17 %

7 0

3 years ago

A liquid has a density of 0.87g/ml. What volume is occupied by 25g of liquid

irga5000 [103]

Answer:

29 mL

Explanation:

<h3>Equation</h3>

The question needs us to find the volume of the liquid. The equation for volume using density and mass is:

Volume = Mass / Density

<h3>Solve</h3>

We can substitute the given values for density and mass into the equation:

$V=\frac{25\ g}{0.87\ g/ml}$

$V\approx29\ mL$

<h3>Additional Comments</h3>

The answer we obtained (29 mL) is rounded to two significant figures. When multiplying or dividing, the amount of significant figures in the final answer is always the least amount of significant figures in one of the values.

Below are the significant figure rules:

Nonzero digits will always be significant (eg. 54 --> 2 significant figures)

Zeroes at the beginning of a number will never be significant (eg. 0.1 --> 1 significant figure)

Zeroes between two nonzero digits will always be significant (eg. 504 --> 3 significant figures)

Zeroes following a number will always be significant if the number contains a decimal point (eg. 40.0 --> 3 significant figures)

5 0

2 years ago