Notice that
11/12 = 1/6 + 3/4
so that
tan(11π/12) = tan(π/6 + 3π/4)
Then recalling that
sin(x + y) = sin(x) cos(y) + cos(x) sin(y)
cos(x + y) = cos(x) cos(y) - sin(x) sin(y)
⇒ tan(x + y) = (tan(x) + tan(y))/(1 - tan(x) tan(y))
it follows that
tan(11π/12) = (tan(π/6) + tan(3π/4))/(1 - tan(π/6) tan(3π/4))
tan(11π/12) = (1/√3 - 1)/(1 + 1/√3)
tan(11π/12) = (1 - √3)/(√3 + 1)
tan(11π/12) = - (√3 - 1)²/((√3 + 1) (√3 - 1))
tan(11π/12) = - (4 - 2√3)/2
tan(11π/12) = - (2 - √3) … … … [A]
Answer: y = 2/5 x + 2
Step-by-step explanation:
why not do this one too yk
slope = y2 - y1 / x2 - x1
4 - 2 / 5 - 0
slope = 2/5
ill use (5,4) for the y=mx+b initial equation
y = mx+b
4 = (2/5)(5) +b
4 = 2 + b
2 = b
now for the final equation whoop whoop
y = 2/5 x + 2
Answer:
-10, -6, 6, 10, 18
Step-by-step explanation:
Answer:
What kind of angles?
Step-by-step explanation:
What is your question?
Not similar one is using a 20 in area and the other is using a 96 in area
