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natita [175]
3 years ago
13

Which type of prevailing wind would carry more water vapor (humidity)? (Choose one)

Chemistry
1 answer:
nirvana33 [79]3 years ago
6 0

Answer:

a. A global wind moving over the ocean

Explanation:

The surface water both north as well as

south of the equator do experience

upwelling. There is a rise of the nutrients to the surface . Ocean surface currents occur as a result of global wind as well as the shape of ocean basin and Coriolis effect

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In adding the measurements 11.074 m, 18.2m, and 16.943 m, what should be the number of scientific figures in the result
Artemon [7]

18.2 is the best answer

6 0
3 years ago
What type of reaction is represented by the following equation:
max2010maxim [7]

Answer:

Acid-base  

Explanation:

KOH is a strong base, and NH₄Cl is an acid. They react to form a salt and water.

KOH + NH₄Cl ⟶ NH₃ + KCl + H₂O

base     acid                    salt   water

6 0
2 years ago
Yes yes yes yes yes yes
sesenic [268]

Answer:

yes yes yes yes yes

Explanation:

Mega yes

5 0
2 years ago
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Imagine that a new planet is discovered with two moons of equal mass: Moon A and Moon B. The mass of the new planet is greater t
kobusy [5.1K]

Answer: The gravitational pull on Moon B is greater than on Moon A because Moon B is closer to the new planet than Moon A.

Explanation:

The gravitational force exerted by the two objects on each other is inversely proportional to the square of the distance between the objects.

F=G\frac{mM}{r^2}

F = gravitational force or pull

G = gravitational constant on that planet

M =  mass of the object-1

m = mass of object-2(Mass of Moon-A or Moon-B)

r = distance between two objects

Force\propto \frac{1}{r^2}

With decease in distance 'r' the force between the object increases or vice versa.So, from this we can say that the gravitational pull on Moon-B is more than the gravitational pull on Moon-A because the Moon B is closer than the Moon-A from the new planet.

3 0
2 years ago
ou will prepare 250-mL of this solution using a 30% (m/v) NaOH stock solution. How many mL of the NaOH stock solution will you n
ArbitrLikvidat [17]

Answer:

\boxed{\text{3.3 mL}}

Explanation:

You must convert 30 % (m/v) to a molar concentration.

Assume 1 L of solution.

1. Mass of NaOH

\text{Mass of NaOH} = \text{1000 mL solution } \times \dfrac{\text{30 g NaOH}}{\text{100 mL solution}} = \text{300 g NaOH}

2. Moles of NaOH  

\text{Moles of NaOH} = \text{300 g NaOH} \times \dfrac{\text{1 mol NaOH}}{\text{40.00 g NaOH}} = \text{7.50 mol NaOH}

3. Molar concentration of NaOH

c= \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{7.50 mol}}{\text{1 L}} = \text{7.50 mol/L}

4. Volume of NaOH

Now that you know the concentration, you can use the dilution formula .

c_{1}V_{1} = c_{2}V_{2}

to calculate the volume of stock solution.

Data:

c₁ = 7.50 mol·L⁻¹; V₁ = ?

c₂ = 0.1   mol·L⁻¹; V₂ = 250 mL

Calculations:

(a) Convert millilitres to litres

V = \text{250 mL} \times \dfrac{ \text{1 L}}{\text{1000 mL}} = \text{0.250 L}

(b) Calculate the volume  of dilute solution

\begin{array}{rcl}7.50V_{1} & = & 0.1 \times 0.250\\7.50V_{1} &= & 0.0250\\V_{1} & = & \text{0.0033 L}\\& = & \textbf{3.3 mL}\\\end{array}

\text{You will need $\boxed{\textbf{3.3 mL}}$ of the stock solution.}

4 0
3 years ago
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