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Marina CMI [18]
3 years ago
8

Which of the following is not a result when a change to an equilibrium system is applied? Increasing the rate of the forward rea

ction will cause a shift to the left. Increasing the rate of the reverse reaction will cause a shift to the left. Decreasing the rate of the forward reaction will cause a shift to the left. Decreasing the rate of the reverse reaction will cause a shift to the right.
Chemistry
2 answers:
kenny6666 [7]3 years ago
5 0

Answer: Increasing the rate of the reverse reaction will cause a shift to the left.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

A+B\leftrightharpoons C+D

For the given options:

Option A: Increasing the rate of the forward reaction will cause a shift to the left.

If the rate of forward reaction is increased, so according to the Le-Chatelier's principle , the equilibrium will shift in the direction where decrease in forward reaction occurs. Hence, the equilibrium will shift in the left direction.

Option B: Increasing the rate of the reverse reaction will cause a shift to the left.

If the rate of reverse reaction is increased, so according to the Le-Chatelier's principle , the equilibrium will shift in the direction where decrease in reverse reaction occurs. Hence, the equilibrium will shift in the right direction.

Option C: Decreasing the rate of the forward reaction will cause a shift to the left

If the rate of forward reaction is decreased, so according to the Le-Chatelier's principle , the equilibrium will shift in the direction where increase in forward reaction occurs. Hence, the equilibrium will shift in the right direction.

Option D: Decreasing the rate of the reverse reaction will cause a shift to the right.

If the rate of reverse reaction is decreased, so according to the Le-Chatelier's principle , the equilibrium will shift in the direction where increase in reverse reaction occurs. Hence, the equilibrium will shift in the left direction.

From the above explanation, we can easily say that the correct answer is Option B.

Scorpion4ik [409]3 years ago
4 0

2) Increasing the rate of the reverse reaction will cause a shift to the left.

Hopefully, If it is wrong my full apologies.



OR IF THATS WRONG, TRY THIS

a - Increasing the rate of the forward reaction will cause equilibrium to be more product-favored (i.e. shift to the right, not the left)

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<u>Answer:</u> The theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of CrO_2 = 480.1 g

Molar mass of CrO_2 = 84 g/mol

Putting values in equation 1, we get:

\text{Moles of }CrO_2=\frac{480.1g}{84g/mol}=5.72mol

For the given chemical equation:

4CrO_2\rightarrow 2Cr_2O_3+O_2

By Stoichiometry of the reaction:

4 moles of CrO_2 produces 2 moles of chromium (III) oxide

So, 5.72 moles of CrO_2 will produce = \frac{2}{4}\times 5.72=2.86mol of chromium (III) oxide

Now, calculating the mass of chromium (III) oxide from equation 1, we get:

Molar mass of chromium (III) oxide = 152 g/mol

Moles of chromium (III) oxide = 2.86 moles

Putting values in equation 1, we get:

2.86mol=\frac{\text{Mass of chromium (III) oxide}}{152g/mol}\\\\\text{Mass of chromium (III) oxide}=(2.86mol\times 152g/mol)=434.72g

To calculate the percentage yield of chromium (III) oxide, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of chromium (III) oxide = 402.4 g

Theoretical yield of chromium (III) oxide = 434.72 g

Putting values in above equation, we get:

\%\text{ yield of chromium (III) oxide}=\frac{402.4g}{434.72g}\times 100\\\\\% \text{yield of chromium (III) oxide}=\%

Hence, the theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

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Answer:

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