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Marina CMI [18]
2 years ago
8

Which of the following is not a result when a change to an equilibrium system is applied? Increasing the rate of the forward rea

ction will cause a shift to the left. Increasing the rate of the reverse reaction will cause a shift to the left. Decreasing the rate of the forward reaction will cause a shift to the left. Decreasing the rate of the reverse reaction will cause a shift to the right.
Chemistry
2 answers:
kenny6666 [7]2 years ago
5 0

Answer: Increasing the rate of the reverse reaction will cause a shift to the left.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

A+B\leftrightharpoons C+D

For the given options:

Option A: Increasing the rate of the forward reaction will cause a shift to the left.

If the rate of forward reaction is increased, so according to the Le-Chatelier's principle , the equilibrium will shift in the direction where decrease in forward reaction occurs. Hence, the equilibrium will shift in the left direction.

Option B: Increasing the rate of the reverse reaction will cause a shift to the left.

If the rate of reverse reaction is increased, so according to the Le-Chatelier's principle , the equilibrium will shift in the direction where decrease in reverse reaction occurs. Hence, the equilibrium will shift in the right direction.

Option C: Decreasing the rate of the forward reaction will cause a shift to the left

If the rate of forward reaction is decreased, so according to the Le-Chatelier's principle , the equilibrium will shift in the direction where increase in forward reaction occurs. Hence, the equilibrium will shift in the right direction.

Option D: Decreasing the rate of the reverse reaction will cause a shift to the right.

If the rate of reverse reaction is decreased, so according to the Le-Chatelier's principle , the equilibrium will shift in the direction where increase in reverse reaction occurs. Hence, the equilibrium will shift in the left direction.

From the above explanation, we can easily say that the correct answer is Option B.

Scorpion4ik [409]2 years ago
4 0

2) Increasing the rate of the reverse reaction will cause a shift to the left.

Hopefully, If it is wrong my full apologies.



OR IF THATS WRONG, TRY THIS

a - Increasing the rate of the forward reaction will cause equilibrium to be more product-favored (i.e. shift to the right, not the left)

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Answer:

a) The pH of the solution is 12.13.

b) The pH of the solution is 12.17.

Explanation:

Ionic product of water =K_w=1.01\times 10^-{14}

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1.01\times 10^-{14}=[H^+][OH^-]

Taking negative logarithm on both sides:

-\log[1.01\times 10^-{14}]=(-\log [H^+])+(-\log [OH^-])

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The pOH is the negative logarithm of hydroxide ion concentration in solution.

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Concentration of hydroxide ions:

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So, [OH^-]=1\times [NaOH]=1\times 1.39\times 10^{-2} M=1.39\times 10^{-2} M

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13.99=pH+1.86

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b) 0.0051 M of NaOH.

Concentration of hydroxide ions:

Al(OH)_3(aq)\rightarrow Al^{3+}(aq)+3OH^-(aq)

So, [OH^-]=3\times [Al(OH)_3]=3\times 0.0051 M=0.0153 M

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13.99=pH+1.82

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Explanation:

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If I dissolve AB in water and form a solution, subsequently, I add solid CB to this solution, the solubility of CB in this solution is found to be lees than the solubility of CB in pure water because of the ion B^- which is common to both substances in solution. We refer to the phenomenon described above as common ion effect.

Common ion effect refers to the decrease in the solubility of a substance in a solution with which it shares a common ion.

If I try to dissolve NaNO2 in a solution of HNO2, the solubility of NaNO2 in the HNO2 solution will be less than its solubility in pure water due to common ion effect. Also, the extent of ionization of HNO2 in a system that already contains NaNO2 will be decreased compared to its extent ionization in pure water. This system described here will contain HNO2, water and NaNO2

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which of the following testable questions will provide evidence that elements in the same group have similar properties?
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  • Complete question here:

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You may find the chemical structure of DDT in the attached figure.

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