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Marina CMI [18]
3 years ago
8

Which of the following is not a result when a change to an equilibrium system is applied? Increasing the rate of the forward rea

ction will cause a shift to the left. Increasing the rate of the reverse reaction will cause a shift to the left. Decreasing the rate of the forward reaction will cause a shift to the left. Decreasing the rate of the reverse reaction will cause a shift to the right.
Chemistry
2 answers:
kenny6666 [7]3 years ago
5 0

Answer: Increasing the rate of the reverse reaction will cause a shift to the left.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

A+B\leftrightharpoons C+D

For the given options:

Option A: Increasing the rate of the forward reaction will cause a shift to the left.

If the rate of forward reaction is increased, so according to the Le-Chatelier's principle , the equilibrium will shift in the direction where decrease in forward reaction occurs. Hence, the equilibrium will shift in the left direction.

Option B: Increasing the rate of the reverse reaction will cause a shift to the left.

If the rate of reverse reaction is increased, so according to the Le-Chatelier's principle , the equilibrium will shift in the direction where decrease in reverse reaction occurs. Hence, the equilibrium will shift in the right direction.

Option C: Decreasing the rate of the forward reaction will cause a shift to the left

If the rate of forward reaction is decreased, so according to the Le-Chatelier's principle , the equilibrium will shift in the direction where increase in forward reaction occurs. Hence, the equilibrium will shift in the right direction.

Option D: Decreasing the rate of the reverse reaction will cause a shift to the right.

If the rate of reverse reaction is decreased, so according to the Le-Chatelier's principle , the equilibrium will shift in the direction where increase in reverse reaction occurs. Hence, the equilibrium will shift in the left direction.

From the above explanation, we can easily say that the correct answer is Option B.

Scorpion4ik [409]3 years ago
4 0

2) Increasing the rate of the reverse reaction will cause a shift to the left.

Hopefully, If it is wrong my full apologies.



OR IF THATS WRONG, TRY THIS

a - Increasing the rate of the forward reaction will cause equilibrium to be more product-favored (i.e. shift to the right, not the left)

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Baking soda (NaHCO3) and vinegar (HC2H3O2) react to form sodium acetate, water, and carbon dioxide. If 42.00 g of baking soda re
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Answer:

0.5 mole of CO₂.

Explanation:

We'll begin by calculating the number of mole in 42 g of baking soda (NaHCO₃). This can be obtained as follow:

Mass of NaHCO₃ = 42 g

Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)

= 23 + 1 + 12 + 48

= 84 g/mol

Mole of NaHCO₃ =?

Mole = mass / molar mass

Mole of NaHCO₃ = 42/84

Mole of NaHCO₃ = 0.5 mole

Next, balanced equation for the reaction. This is given below:

NaHCO₃ + HC₂H₃O₂ → NaC₂H₃O₂ + H₂O + CO₂

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂

Finally, we shall determine the number of mole of CO₂ produced by the reaction of 42 g (i.e 0.5 mole) of NaHCO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.

Therefore, 0.5 mole of NaHCO₃ will also react to produce 0.5 mole of CO₂.

Thus, 0.5 mole of CO₂ was obtained from the reaction.

7 0
3 years ago
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