1s2,2s2.2p6,3s2,3p6,3d4,4s2
There are 14 atoms, the 2 at the front times' everything by 2, so there 4Ks, 2Ss and 8Os, altogether 14
1.1 moles of C10H8 is the limiting reagent in the reaction between reaction C10H8 and O2
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C10H8 + 12O2 ----> 10CO2 + 4H2O
C10H8 is the limiting reagent since 1.1 moles of C10H8 is totally consumed during the reaction
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